1.-x[6+(4*2)]-5, first do the things in the parenthesis: 4*2=8, then +6=14 then *-x=-14x and keep the -5
-14x-5
Answer:
17.1972degrees
Step-by-step explanation:
length of an arc = theta/360 * 2πr
Substitute the given angle;
1.2 = theta/360 * 2(3.14)(4)
1.2 = theta/360 * 25.12
1.2/25.12 = theta/360
0.04777 = theta/360
theta = 360 * .04777
theta = 17.1972
Hence the required angle is 17.1972degrees
3y+15=4y-3
Subtract 3y from both sides
15=y-3
Add 3 to both sides
Y=18
4(18)-3
72-3
69 both angles are 69
Answer:
B(-6, 0)
Step-by-step explanation:
You want to find B such that ...
(B -A) = (3/4)(C -A) . . . . the required distance relation
4(B -A) = 3(C -A) . . . . . . multiply by 4
4B = 3C +A . . . . . . . . . . add 4A, simplify
Now, we can solve for B and substitute the given coordinates:
B = (3C +A)/4 = (3(-6, -2) +(-6, 6))/4 = (-24, 0)/4 = (-6, 0)
The coordinates of point B are (-6, 0).
Hope it helped u if yes mark me BRAINLIEST!
Tysm!
:D
I = PRT....for R....divide both sides by PT
I / PT = R <==
