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Alex777 [14]
3 years ago
7

Methane and ethane are both made up of carbon and hydrogen. In methane, there are 12.0 g of carbon for every 4.00 g of hydrogen,

a ratio of 3:1 by mass. In ethane, there are 24.0 g of carbon for every 6.00 g of hydrogen, a ratio of 4:1 by mass. This is an illustration of the law of __________.
Chemistry
1 answer:
Sati [7]3 years ago
8 0

Answer:

The answer is: Law of multiple proportions        

Explanation:

The law of multiple proportions is a law of chemical combination given by Dalton in 1803.

According to this law, if more than one chemical compound is formed by combining two elements, then the mass of an element that combines with the fixed mass of other element is represented in the form of small whole number ratio.

<u>Therefore, is an illustration of the law of the law of multiple proportions.</u>

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Howmany copper atoms there is in Copper(II) oxide?​
Oxana [17]

Answer:

copper(ll) has 4 oxygen atoms

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Write down the simple electron configurations of
vitfil [10]
B is the correct answer
5 0
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30 g of Magnesium and 30 g of Oxygen are reacted,<br> then the residual mixture contains
Alecsey [184]

Answer:

2Mg + O2 -> 2MgO

Explanation:

According to the above reaction ,

28.6g(2mole) Mg combine with 32g (1mole) of O2 to give 80.6g (2 mole) of MgO.

thus,

30g Mg will combine with 20g of O2 to produce 50g MgO and 10gO2 will remain unreactive.

I hope it's helpful!

5 0
3 years ago
In 2021, you were given a 100. g wine sample to verify its age. Using tritium dating you observe that the sample has 0.688 decay
nikdorinn [45]

Answer:

1984

Explanation:

Given the formula;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2 = half life of the radioactive isotope

t= age of the wine

Ao= initial activity of the wine

A= activity of the at time = t

0.693/12.3 = 2.303/t log (5.5/0.688)

0.693/12.3 = 2.079/t

0.056 = 2.079/t

t= 2.079/0.056

t= 37 years

The wine was produced 37 years ago which means that it was produced in the year 1984

7 0
3 years ago
An electron in an atom is known to be in a state with magnetic quantum number ml=0. What is the smallest possible value of the p
rusak2 [61]

Answer:

1

Explanation:

The principal quantum number, n, showsthe principal electron shell. which can inturn be describe as the most probable distance of the electrons from the nucleus, the larger the number n is, the farther the electron is from the nucleus, the larger the size of the orbital, and the larger the atom is. n can be any positive integer starting at 1, as n=1 designates the first principal shell (the innermost shell). When an electron is in an excited state or it gains energy, it may jump to the second principle shell, where n=2

As the energy of the electron increases, so does the principal quantum number, e.g., n = 3 indicates the third principal shell, n = 4 indicates the fourth principal shell, and so on. n=1,2,3,4…

On the other hand, the magnetic quantum number ml determines the number of orbitals and their orientation within a subshell. Consequently, its value depends on the orbital angular momentum quantum number l. Given a certain l, ml is an interval ranging from –l to +l, so it can be zero, a negative integer, or a positive integer. ml=−l,(−l+1),(−l+2),…,−2,−1,0,1,2,…(l–1),(l–2),+l

note also that: The orbital angular momentum quantum number l determines the shape of an orbital, and therefore the angular distribution. The number of angular nodes is equal to the value of the angular momentum quantum number l. Each value of l indicates a specific s, p, d, f subshell (each unique in shape.) The value of l is dependent on the principal quantum number n. Unlike n, the value of l can be zero. It can also be a positive integer, but it cannot be larger than one less than the principal quantum number (n-1): l=0,1,2,3,4…,(n−1).

So the answer is 1

3 0
4 years ago
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