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Elan Coil [88]
3 years ago
11

An object reference provides a(an)______for an object and is used to gain access to the object (Points : 2) entry

Computers and Technology
1 answer:
sdas [7]3 years ago
3 0

Answer: Instance

Explanation: Instance is the term found in the object-orient programming concept. It is used for the realization of the variation present in any object specifically.The program execution at each time instant is known as the instance of program. Generation of realized instance is known as instantiation.

This helps in the accessing of the object in the program.Other options are incorrect entry , target and handle are not the technical term related with the accessing of object .Thus the correct answer is instance.

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Which of the following transferable skills are generally the most looked for in the IT field?
san4es73 [151]
The correct option is D.
Transferable skills refers to those set of skills that do not belong to any specific field or industry, they are general skills and can be transferred from one job to another. Option D is the correct choice because all jobs require the employees to have problem solving skill, team building skills and communication skills; all these skills contribute to a successful career. 
3 0
3 years ago
Read 2 more answers
Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl
Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

    small = num1

    if num1 > num2:

         small = num2

    for i in range(1, small+1):

         if((num1 % i == 0) and (num2 % i == 0)):

              gcd = i

    print("The GCD is "+ str(gcd))

def LCM(num1,num2):

    big = num2  

    if num1 > num2:

         big = num1

    while(True):

         if((big % num1 == 0) and (big % num2 == 0)):

              lcm = big

              break

         big = big+1

     print("The LCM is "+ str(lcm))

 print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

    small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

<em>     if num1 > num2: </em>

<em>          small = num2 </em>

The following iteration determines the GCD of num1 and num2

<em>     for i in range(1, small+1): </em>

<em>          if((num1 % i == 0) and (num2 % i == 0)): </em>

<em>               gcd = i </em>

This line prints the GCD

    print("The GCD is "+ str(gcd))

   

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

    big = num2  

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

<em>     if num1 > num2: </em>

<em>          big = num1 </em>

The following iteration continues while the LCM has not been gotten.

    while(True):

This if statement determines the LCM using modulo operator

<em>          if((big % num1 == 0) and (big % num2 == 0)): </em>

<em>               lcm = big </em>

<em>               break </em>

<em>          big = big+1 </em>

This line prints the LCM of the two numbers

     print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

<em></em>

<em>See attachment for more structured program</em>

Download txt
5 0
3 years ago
Q1). Write a python program to pass a list to a function and double the odd values and half even values of a list and display li
zepelin [54]

Answer:

\textsf{\large{\underline{Solution}:}}

The given problem is solved using language - Python.

def f(x):

   new_list=[]

   for i in x:

       if i%2==0:

           new_list.append(i//2)

       else:

           new_list.append(i*2)

   return new_list

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(my_list)

print('Modified List:',my_list)

\textsf{\large{\underline{Logic}:}}

  1. Create a new list.
  2. Iterate over the list passed into the function.
  3. Check if the element is even or not. If true, append half the value of element in the list.
  4. If false, append twice the value of the element in the list.
  5. At last, return the new list.

There is another way of doing this - By using map() function.

—————————————————————————————

def f(x):

   return list(map(lambda x:x//2 if x%2==0 else 2*x,x))

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(2my_list)

print('Modified List:',my_list)

—————————————————————————————

\textsf{\large{\underline{O{u}tput}:}}

Original List: [1, 2, 3, 4, 5]

Modified List: [2, 1, 6, 2, 10]

8 0
3 years ago
Tamera was responding to a complaint that one of the employees is having problems with the wired network connection on their lap
WARRIOR [948]

Answer:

tamera like from sister sister hehe

Explanation:

sorry i dont know the awnser

3 0
3 years ago
Siltstone is made mostly of _____.<br><br> A : silt<br> B : sand<br> C : shells<br> D : gravel
frez [133]
The best and most correct answer among the choices provided by the question is the second choice. <span>Siltstone is made mostly of silt. </span>I hope my answer has come to your help. God bless and have a nice day ahead!
6 0
3 years ago
Read 2 more answers
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