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3 years ago

An object reference provides a(an)______for an object and is used to gain access to the object (Points : 2) entry

Computers and Technology

1 answer:

sdas [7]3 years ago

3 0

Answer: Instance

Explanation: Instance is the term found in the object-orient programming concept. It is used for the realization of the variation present in any object specifically.The program execution at each time instant is known as the instance of program. Generation of realized instance is known as instantiation.

This helps in the accessing of the object in the program.Other options are incorrect entry , target and handle are not the technical term related with the accessing of object .Thus the correct answer is instance.

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Which of the following transferable skills are generally the most looked for in the IT field?

san4es73 [151]

The correct option is D.
Transferable skills refers to those set of skills that do not belong to any specific field or industry, they are general skills and can be transferred from one job to another. Option D is the correct choice because all jobs require the employees to have problem solving skill, team building skills and communication skills; all these skills contribute to a successful career.

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3 years ago

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Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl

Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

small = num1

if num1 > num2:

small = num2

for i in range(1, small+1):

if((num1 % i == 0) and (num2 % i == 0)):

gcd = i

print("The GCD is "+ str(gcd))

def LCM(num1,num2):

big = num2

if num1 > num2:

big = num1

while(True):

if((big % num1 == 0) and (big % num2 == 0)):

lcm = big

break

big = big+1

print("The LCM is "+ str(lcm))

print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

if num1 > num2:

small = num2

The following iteration determines the GCD of num1 and num2

for i in range(1, small+1):

if((num1 % i == 0) and (num2 % i == 0)):

gcd = i

This line prints the GCD

print("The GCD is "+ str(gcd))

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

big = num2

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

if num1 > num2:

big = num1

The following iteration continues while the LCM has not been gotten.

while(True):

This if statement determines the LCM using modulo operator

if((big % num1 == 0) and (big % num2 == 0)):

lcm = big

break

big = big+1

This line prints the LCM of the two numbers

print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

See attachment for more structured program

Download txt

5 0

3 years ago

Q1). Write a python program to pass a list to a function and double the odd values and half even values of a list and display li

zepelin [54]

Answer:

$\textsf{\large{\underline{Solution}:}}$

The given problem is solved using language - Python.

def f(x):

new_list=[]

for i in x:

if i%2==0:

new_list.append(i//2)

else:

new_list.append(i*2)

return new_list

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(my_list)

print('Modified List:',my_list)

$\textsf{\large{\underline{Logic}:}}$

Create a new list.
Iterate over the list passed into the function.
Check if the element is even or not. If true, append half the value of element in the list.
If false, append twice the value of the element in the list.
At last, return the new list.

There is another way of doing this - By using map() function.

—————————————————————————————

def f(x):

return list(map(lambda x:x//2 if x%2==0 else 2*x,x))

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(2my_list)

print('Modified List:',my_list)

—————————————————————————————

$\textsf{\large{\underline{O{u}tput}:}}$

Original List: [1, 2, 3, 4, 5]

Modified List: [2, 1, 6, 2, 10]

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3 years ago

Tamera was responding to a complaint that one of the employees is having problems with the wired network connection on their lap

WARRIOR [948]

Answer:

tamera like from sister sister hehe

Explanation:

sorry i dont know the awnser

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3 years ago

Siltstone is made mostly of _____. A : silt B : sand C : shells D : gravel

frez [133]

The best and most correct answer among the choices provided by the question is the second choice. Siltstone is made mostly of silt. I hope my answer has come to your help. God bless and have a nice day ahead!

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3 years ago

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