The square of a prime number is not prime.
a) let x ∈ R, If x ∈ {prime numbers}, then 
∉{prime numbers}
there says that if x is a real and x is in the set of the prime numbers, then the square of x isn't in the set of prime numbers.
b) Prove or disprove the statement.
ok, if x is a prime number, then x only can be divided by himself. Now is easy to see that = x*x can be divided by himself and x, then x*x is not a prime number, because can be divided by another number different than himself
I think the answer is the Last one
Answer:
y=2x+5
Step-by-step explanation:
The equation of a line in slope intercept form is written as: y=mx +b where m is the slope and b is the y-intercept.
Taking point (-1,3) , m= 2 and imaginary point on the line, (x,y) then ;
m=change is y-coordinates/change in x-coordinate
m=Δy/Δx
m=y-3/x--1
2= y-3 / x+1
2(x+1) = y-3
2x +2 =y-3
2x=y-3-2
2x=y-5
<u>y=2x+5 is the equation.</u>
