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allsm [11]
3 years ago
5

The most active metals on the periodic table are found on the: lower left upper right middle upper left lower right

Chemistry
2 answers:
loris [4]3 years ago
7 0

Answer: Option (a) is the correct answer.

Explanation:

Elements which are most electropositive or electronegative are the most reactive in nature. Therefore, they are active.

Elements of group 1 are also known as alkali metals. Elements of group 1 are lithium, sodium, potassium, rubidium, cesium, and francium.

All these are highly electropositive in nature and thus, are active. These are placed at the top left column of periodic table.

Thus, we can conclude that out of the given options, the most active metals on the periodic table are found on the lower left.

andreev551 [17]3 years ago
4 0

<u>Answer:</u> The correct answer is lower left.

<u>Explanation:</u>

Metals are defined as the elements which loose electrons to attain stable electronic configuration.

Reactivity of metals is defined as the tendency of metals to loose electrons. If a metal looses electrons easily, it means that it is more reactive.

Reactivity increases down the group and decreases across a period for metals.

In the periodic table attached,

  • The elements present in lower left are metals which are most reactive.
  • The elements present in upper right are non-metals which are most reactive.
  • The elements present in middle are metals which are less reactive.
  • The elements present in upper left are metals which are least reactive reactive.
  • The elements present in lower right are non-metals which are least reactive.

Hence, the correct answer is lower left.

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A gas has a volume of 5.00 L at 20.0oC. If the gas is compressed to 4.0 L, what is the new temperature of the gas in Kelvin?
Tatiana [17]

Answer: 234.4K

Explanation:

Given that,

Original volume of gas (V1) = 5.00 L

Original temperature of gas (T1) = 20.0°C

[Convert 20.0°C to Kelvin by adding 273

20.0°C + 273 = 293K]

New volume of gas (V2) = 4.0L

New temperature of gas (T2) = ?

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

5.00L/293K = 4.0L/T2

To get the value of T2, cross multiply

5.00L x T2 = 293K x 4.0L

5.00L•T2 = 1172L•K

Divide both sides by 5.00L

5.00L•T2/5.00L = 1172L•K/5.00L

T2 = 234.4K

Thus, the new temperature of the gas is 234.4 Kelvin

8 0
3 years ago
Why do we use ammonium formate as a hydrogen surrogate instead of using hydrogen gas in this experiment?
NemiM [27]

Answer:

Ammonium formate can also be used in palladium on carbon (Pd/C) reduction of functional groups. In the presence of Pd/C, ammonium formate decomposes to hydrogen, carbon dioxide, and ammonia.

Explanation:

This hydrogen gas is adsorbed onto the surface of the palladium metal, where it can react with various functional groups.

7 0
3 years ago
Hi can you slove this please. ..​
Crank

Answer : The balanced chemical equation will be:

(i) 2K+H_2SO_4\rightarrow K_2SO_4+H_2

(ii) Mg(OH)_2+Zn\rightarrow Zn(OH)_2+Mg

Explanation :

Balanced chemical equation : It is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

Part (i):

The balanced chemical equation will be:

2K+H_2SO_4\rightarrow K_2SO_4+H_2

This reaction is a single displacement reaction in which most reactive element (potassium) displaces the least reactive element (hydrogen) form their solution.

Part (ii):

The balanced chemical equation will be:

Mg(OH)_2+Zn\rightarrow Zn(OH)_2+Mg

This reaction is a single displacement reaction in which most reactive element (zinc) displaces the least reactive element (magnesium) form their solution.

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4 years ago
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This book is printed on acid-free paper.

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umka21 [38]

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