Answer: 234.4K
Explanation:
Given that,
Original volume of gas (V1) = 5.00 L
Original temperature of gas (T1) = 20.0°C
[Convert 20.0°C to Kelvin by adding 273
20.0°C + 273 = 293K]
New volume of gas (V2) = 4.0L
New temperature of gas (T2) = ?
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
5.00L/293K = 4.0L/T2
To get the value of T2, cross multiply
5.00L x T2 = 293K x 4.0L
5.00L•T2 = 1172L•K
Divide both sides by 5.00L
5.00L•T2/5.00L = 1172L•K/5.00L
T2 = 234.4K
Thus, the new temperature of the gas is 234.4 Kelvin
Answer:
Ammonium formate can also be used in palladium on carbon (Pd/C) reduction of functional groups. In the presence of Pd/C, ammonium formate decomposes to hydrogen, carbon dioxide, and ammonia.
Explanation:
This hydrogen gas is adsorbed onto the surface of the palladium metal, where it can react with various functional groups.
Answer : The balanced chemical equation will be:
(i) 
(ii) 
Explanation :
Balanced chemical equation : It is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.
Part (i):
The balanced chemical equation will be:

This reaction is a single displacement reaction in which most reactive element (potassium) displaces the least reactive element (hydrogen) form their solution.
Part (ii):
The balanced chemical equation will be:

This reaction is a single displacement reaction in which most reactive element (zinc) displaces the least reactive element (magnesium) form their solution.
The answer is D.1.950 g
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Answer: He(g)
Explanation: I had the same question and I got the answer right