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allsm [11]
3 years ago
5

The most active metals on the periodic table are found on the: lower left upper right middle upper left lower right

Chemistry
2 answers:
loris [4]3 years ago
7 0

Answer: Option (a) is the correct answer.

Explanation:

Elements which are most electropositive or electronegative are the most reactive in nature. Therefore, they are active.

Elements of group 1 are also known as alkali metals. Elements of group 1 are lithium, sodium, potassium, rubidium, cesium, and francium.

All these are highly electropositive in nature and thus, are active. These are placed at the top left column of periodic table.

Thus, we can conclude that out of the given options, the most active metals on the periodic table are found on the lower left.

andreev551 [17]3 years ago
4 0

<u>Answer:</u> The correct answer is lower left.

<u>Explanation:</u>

Metals are defined as the elements which loose electrons to attain stable electronic configuration.

Reactivity of metals is defined as the tendency of metals to loose electrons. If a metal looses electrons easily, it means that it is more reactive.

Reactivity increases down the group and decreases across a period for metals.

In the periodic table attached,

  • The elements present in lower left are metals which are most reactive.
  • The elements present in upper right are non-metals which are most reactive.
  • The elements present in middle are metals which are less reactive.
  • The elements present in upper left are metals which are least reactive reactive.
  • The elements present in lower right are non-metals which are least reactive.

Hence, the correct answer is lower left.

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Which action would shift this reaction away from solid calcium fluoride and toward the dissolved ions?a) adding calcium ionsb) a
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Answer:

c) removing fluoride ions.

Explanation:

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In this case, for this solubility product problem, it is very convenient to write the undergoing ionization reaction:

CaF_2(s)\rightleftharpoons Ca^{2+}(aq)+2F^-(aq)

In such a way, via the Le Chatelier's principle, we remember that the addition of reactants shifts the reaction towards products, adding products shifts the reaction towards reactants, removing reactants shifts the reaction towards reactants and removing products shifts the reaction towards products. In means, that the best way to shift this reaction away from solid calcium fluoride and toward the dissolved ions is c) removing fluoride ions, because it is a product and its removal favors the formation of more products.

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4 years ago
Four research teams measured the length of a rare whale, and what each team wrote in its team notebook is shown in the table bel
vovikov84 [41]

Answer:

Explanation:

Precision relates to instruments of measurement or scale . A scale measuring upto cm is less precise than an instrument measuring upto mm .

Here the first measurement appears to have been taken with an instrument measuring up to metre and the second measurement appears to have been taken with an instrument measuring up to decimeter . So second measurement is most precise .

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3 years ago
What is the goal of mitosis? Of meiosis?
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a bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be rel
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<h3>Answer:</h3>

4.56 × 10^-19 Joules

<h3>Explanation:</h3>

We are given;

  • Wavelength of the wave as 435.8 nm

We are required to calculate the amount of energy released by an electron.

  • We know that the speed of the wave, c is 2.998 × 10^8 m/s
  • But, c = f × λ , where f is the frequency and λ is the wavelength
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E = hf , where h is the plank's constant, 6.626 × 10^-34 J-s

But, f = c/λ

Therefore;

f = (2.998 × 10^8 m/s) ÷ (4.358 × 10^-7 m)

  = 6.879 × 10^14 Hz

Thus;

Energy = 6.626 × 10^-34 J-s ×6.879 × 10^14 Hz

            = 4.558 × 10^-19 Joules

            =  4.56 × 10^-19 Joules

Therefore, the energy that must be released by the electron is 4.56 × 10^-19 Joules

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