Answer:
c) removing fluoride ions.
Explanation:
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In this case, for this solubility product problem, it is very convenient to write the undergoing ionization reaction:

In such a way, via the Le Chatelier's principle, we remember that the addition of reactants shifts the reaction towards products, adding products shifts the reaction towards reactants, removing reactants shifts the reaction towards reactants and removing products shifts the reaction towards products. In means, that the best way to shift this reaction away from solid calcium fluoride and toward the dissolved ions is c) removing fluoride ions, because it is a product and its removal favors the formation of more products.
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Answer:
Explanation:
Precision relates to instruments of measurement or scale . A scale measuring upto cm is less precise than an instrument measuring upto mm .
Here the first measurement appears to have been taken with an instrument measuring up to metre and the second measurement appears to have been taken with an instrument measuring up to decimeter . So second measurement is most precise .
Third measurement is closest to the actual measurement that is 45.0 m , so it is most accurate measurement .
The main goal of mitosis is to line up duplicated chromosomes and to split them equally, resulting in two cells with the same number of chromosomes
The answer is b because I learned this in 5th grade and I got it right
<h3>
Answer:</h3>
4.56 × 10^-19 Joules
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Explanation:</h3>
We are given;
- Wavelength of the wave as 435.8 nm
We are required to calculate the amount of energy released by an electron.
- We know that the speed of the wave, c is 2.998 × 10^8 m/s
- But, c = f × λ , where f is the frequency and λ is the wavelength
- Energy of a wave is given by the formula;
E = hf , where h is the plank's constant, 6.626 × 10^-34 J-s
But, f = c/λ
Therefore;
f = (2.998 × 10^8 m/s) ÷ (4.358 × 10^-7 m)
= 6.879 × 10^14 Hz
Thus;
Energy = 6.626 × 10^-34 J-s ×6.879 × 10^14 Hz
= 4.558 × 10^-19 Joules
= 4.56 × 10^-19 Joules
Therefore, the energy that must be released by the electron is 4.56 × 10^-19 Joules