Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.
Explanation :
(a) At constant volume condition the entropy change of the gas is:
We know that,
The relation between the 
for an ideal gas are :
As we are given :
Now we have to calculate the entropy change of the gas.
(b) As we know that, the work done for isochoric (constant volume) is equal to zero. 
(C) Heat during the process will be,
Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.
Answer:
for the reaction is 18.05
Explanation:
Equilibrium constant in terms of partial pressure () for this reaction can be written as-
where 
and 
are equilibrium partial pressure of 
and 
respectively
Hence 
= 18.05
So, for the reaction is 18.05
Maybe gas? because you can’t see it and it’s formed during a chemical reaction
In chemistry and atomic physics, the main group is the group of elements whose lightest members are represented by helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, and fluorine as arranged in the periodic table of the elements
la vaina esa es de la A no le pare loco
