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4 years ago

Suppose you have a mole of uranium (U) and three moles of hydrogen (H). Do you have

Chemistry

1 answer:

julia-pushkina [17]4 years ago

3 0

Answer:

Explanation:

A mole is a measure of a number of atoms. One mole of Uranium is the same number of atoms as one mole of Hydrogen

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Carbonyl sulfide has the chemical formula COS. Carbon has four valence electrons, and oxygen and sulfur each have six valence el

FrozenT [24]

Answer:

The attached image should be your answer for the Lewis Structure of COS

Explanation:

3 0

3 years ago

Read 2 more answers

The thermostat in a refrigerator filled with cans of soft drinks malfunctions and the temperature of the refrigerator drops belo

butalik [34]

Answer:

Explanation:

Water expands on freezing and there is more water in the diet drinks than in the other drinks.

5 0

3 years ago

Read 2 more answers

In an experiment, a student made a compund of sulfur and copper, and now she needs to find if the compound is copper (I) sulfide

finlep [7]

Answer: The formula for the given compound is $Cu_2S$

Explanation:

An ionic compound is defined as the compound which is formed when electron gets transferred from one atom to another atom. These are usually formed when a metal reacts with a non-metal.

The chemical formula of copper (I) sulfide is $Cu_2S$ because this is formed by the combination of $Cu^+$ ions and $S^{2-}$ ions

The chemical formula of copper (II) sulfide is $CuS$ because this is formed by the combination of $Cu^{2+}$ ions and $S^{2-}$ ions

To calculate the percent composition of element in a compound, we use the equation:

$\text{Percent composition of element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100$ ...........(1)

For copper (I) sulfide:

Mass of copper = (2 × 63.546) = 127.092 g/mol

Mass of copper (I) sulfide = 159.16 g/mol

Putting values in equation 1, we get:

$\text{Percent composition of copper in }Cu_2S=\frac{127.092g}{159.16g}=79.85\%$

For copper (II) sulfide:

Mass of copper = 63.546 g/mol

Mass of copper (II) sulfide = 95.611 g/mol

Putting values in equation 1, we get:

$\text{Percent composition of copper in CuS}=\frac{63.546g}{95.611g}=66.46\%$

Given compound:

Mass of copper in given compound = 0.8383 grams

Mass of given compound = 1.0440 grams

Putting values in equation 1, we get:

$\text{Percent composition of copper in given compound}=\frac{0.8383g}{1.044g}=80.29\%$

The percent composition of copper is close to the composition in copper (I) sulfide.

Hence, the formula for the given compound is $Cu_2S$

8 0

3 years ago

What do many bases have in common?

Olin [163]

Answer:

D.) They often form hydroxide ions.

Explanation:

They generate hydroxide ions in water. they are soapy to touch and bitter in taste. they conduct electricity.

(all bases have hydroxide ions)

7 0

3 years ago

Find the exact value of x

Semmy [17]

Answer:

Explanation:

I am not sure this is a simple answer

5 0

3 years ago