Answer:
(B) the energy required to break apart one mole of an ionic compound into its gaseous ions
Explanation:
Lattice energy is the energy that would be obtained from the formation of an ionic compound from its gaseous ions. Therefore, the reverse process that responds the question would be the energy required to break apart an ionic compound and convert its component atoms into gaseous ions.
Lattice energy provides a measure of the stability of an ionic compound. When the ions bind to form the crystalline structure, heat (energy) is released. To break the ionic compound into the ions that form it, it is necessary to provide an energy equal to that released when formed, i.e. the lattice energy.
Explanation:
Since, aluminium chloride is an eye and skin irritant. Therefore, it is better to follow safety measures while dealing with such a chemical.
Hence, it is good to wear a lab coat while working in a laboratory and wear chemical resistant gloves so that our skin does not come in contact with the chemical.
Also, safety glasses will prevent the eyes if there is spurting of chemical.
Thus, we can conclude that chemical-resistant gloves, a lab coat, and safety glasses will prevent you from coming into contact with the given hazard.
I have no skins for you my brother and my girlfriend and my uncle are going out and have you come on the house for me to do you have to get on your phone
Answer:
8 moles of C
Explanation:
From the question given above, the following equation was obtained:
3A + 2B —> 6C
From the equation above,
3 moles of A reacted to produce 6 moles of C.
Thus, the number of mole of C produced by reacting 4 moles of A can be obtained as follow:
From the equation above,
3 moles of A reacted to produce 6 moles of C.
Therefore, 4 moles of C will react to produce = (4 × 6)/3 = 8 moles of C
Thus, 8 moles of C can be obtained from the reaction of 4 moles of A with excess B
Answer:
0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl
Explanation:
The balanced reaction is:
Mg + 2 HCl → MgCl₂ + H₂
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles react:
- Mg: 1 mole
- HCl: 2 moles
- MgCl₂: 1 mole
- H₂: 1 mole
Being:
- Mg: 24. 31 g/mole
- H: 1 g/mole
- Cl: 35.45 g/mole
the molar mass of the compounds participating in the reaction is:
- Mg: 24.31 g/mole
- HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
- MgCl₂: 24.31 g/mole + 2*35.45 g/mole= 95.21 g/mole
- H₂: 2*1 g/mole= 2 g/mole
Then, by stoichiometry of the reaction, the following quantities of mass participate in the reaction:
- Mg: 1 mole* 24.31 g/mole= 24.31 g
- HCl: 2 moles* 36.45 g/mole= 72.9 g
- MgCl₂: 1 mole* 95.21 g/mole= 95.21 g
- H₂: 1 mole* 2 g/mole= 2 g
Then you can apply the following rule of three: if by stoichiometry 24.31 grams of Mg form 1 mole of H₂, 3.25 grams of Mg how many moles of H₂ will they form?
moles of H₂= 0.134
<u><em>0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl</em></u>
