There are 3 major parts of the respiratory system: the airway, the lungs, and the muscles of respiration. The airway, which includes the nose, mouth, pharynx, larynx, trachea, bronchi, and bronchioles, carries air between the lungs and the body's exterior.
Q1. The answer is 1.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
x = 50% = 50/100 = 0.5
n = ?
(1/2)ⁿ = 0.5
log((1/2)ⁿ) = log(0.5)
n * log(1/2) = log(0.5)
n * log(0.5) = log(0.5)
n = log(0.5)/log(0.5)
n = 1
Q10. The answer is 2.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
Rhyolite #2 has 25% of the parent H remaining:
x = 25% = 25/100 = 0.25
n = ?
(1/2)ⁿ = 0.25
log((1/2)ⁿ) = log(0.25)
n * log(1/2) = log(0.25)
n * log(0.5) = log(0.25)
n = log(0.25)/log(0.5)
n = -0.602 / - 0.301
n = 2
Q3. The answer is 100 million years.
A number of half-lives (n) is a quotient of total time elapsed (t) and length of half-life (H):
n = t/H
n = 1
t = ?
H = 100 000 000 years
n = t/H
t = n * H
t = 1 * 100 000 000 years
t = 100 000 000 years<span>
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Answer:
C. Both of the above.........
Answer:
See explanation
Explanation:
We inherit our blood groups from both parents. Our blood type is controlled by a single gene. This gene displays 3 different allelic pairs which must include A, B or O. A child is expected to receive one of the three possible allelic pairs from each of the both parents. This means that there are six possible genotype and four possible phenotype for the child.
Given that Christopher's parents (Andersons) are AB and O,Christopher can have a B blood group.
Given that John's parents (Browns) are A and O, it explains how John can have blood group A.
Given that The Christiansons are A and AB, they can give birth to Robin whose blood group is AB.
Since the Dietrichs are O and O, the only possible blood group of their child is O, hence they are definitely the parents of Jane.
im not to sure, but i think its 21.95
hope this helps! :)
