3 years ago

SOMEONE HELP.Whos good with parallelogram.Need good answer

Mathematics

1 answer:

sashaice [31]3 years ago

8 0

Yes that is a parallelogram

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Evaluate the integral using integration by parts with the indicated choices of u and dv. (Use C for the constant of integration.

Aleksandr-060686 [28]

Take

$u=\ln x\implies\mathrm du=\dfrac{\mathrm dx}x$

$\mathrm dv=4x^2\,\mathrm dx\implies v=\dfrac43x^3$

Then

$\displaystyle\int4x^2\ln x\,\mathrm dx=\frac43x^3\ln x-\frac43\int x^2\,\mathrm dx=\frac43x^3\ln x-\frac49x^3+C$

$=\boxed{\dfrac49x^3(3\ln x-1)+C}$

5 0

3 years ago

I'm stuck please i need help and it's urgent

NNADVOKAT [17]

Answer:

x²=2x-1>>

x²-2x+1=0

x=1

y²-4 = 5x>>

y²= 5×1+4=9

y=3

x_2=z-2>>

z=x=1

4 0

3 years ago

Find the area of the figure pictured below.

Tomtit [17]

Answer:

64 square units

Step-by-step explanation:

Split the figure into 2 rectangles of dimensions:

4 × 10

8 × 3

And solve.

(4 × 10) + (8 × 3) = 40 + 24 = 64 square units

See the attached image for a model.

4 0

1 year ago

What is the value of 2x^-2y^-2 for x = 3 and y = 2? a) 1/18 b) 72 c) 2(-6)^-4 d) 1/648

sladkih [1.3K]

2x^-2y^-2 = 2/x^2y^2 = 2/(2)^2 x (3)2 = 2/4 x 9 = 2/36 = 1/18

8 0

3 years ago

Which of the following is in the solution set of the inequality –28 < v – 16

exis [7]

Let's solve your inequality step-by-step.−28<v−16
Step 1: Flip the equation.v−16>−28
Step 2: Add 16 to both sides.v−16+16>−28+16
v>−12
Answer:v>−12

6 0

3 years ago

Read 2 more answers

SOMEONE HELP.Whos good with parallelogram.Need good answer​

SOMEONE HELP.Whos good with parallelogram.Need good answer