Answer:
See explanation
Explanation:
Substances are composed of bands. A band is a group of molecular orbitals, the energy differences between them are so small that the system behaves as if a continuous, non-quantization of energy within the barrier is possible.
Materials consists of a valence band and a conduction band separated by a band gap. A band gap occurs when the energy difference between two bands is significant.
The magnitude of band gap determines whether a material will be a metal, nonmetal or metalloid.
Metals have a very little band gap hence they are able to conduct electricity more effectively than other materials, such as ionic and covalent substances.
It's known as "<span>ionization energy</span><span>", I believe. </span>
Answer:
A. 0.1 M
Explanation:
Given data
- Mass of NaI (solute): 15 g
- Molar mass of NaI: 150 g/mol
Step 1: Calculate the moles of solute
Step 2: Calculate the molarity of the solution
The molarity of the solution is equal to the moles of solute divided by the liters of solution.
The solution is 0.1 M.
Answer:
The volume of solution in liters required to make a 0.250 M solution from 3.52 moles of solute is 14.08 liters of solution
Explanation:
The question relates to the definition of the concentration of a solution which is the number of moles per liter (1 liter = 1 dm³) of solution
Therefore we have;
The concentration of the intended solution = 0.250 M
Therefore, the number of moles per liter of the required resolution = 0.250 moles
Therefore, the concentration of the required solution = 0.250 moles/liter
The volume in liters of the required solution that will have 3.52 moles of the solute is given as follows;
The required volume of solution = The number of moles of the solute/(The concentration of the solution)
∴ The required volume of solution = 3.52 moles/(0.250 moles/liter) = 14.08 liters
The required volume of solution to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.
Therefore the number of liters required to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.
