Please help with these asap
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1.70 × 10³ seconds
<h3>Explanation </h3> + 2 e⁻ →
It takes two moles of electrons to reduce one mole of cobalt (II) ions and deposit one mole of cobalt.
Cobalt has an atomic mass of 58.933 g/mol. 0.500 grams of Co contains of Co atoms. It would take
of electrons to reduce cobalt (II) ions and produce the
of cobalt atoms.
Refer to the Faraday's constant, each mole of electrons has a charge of around 96 485 columbs. The 0.01697 mol of electrons will have a charge of . A current of 0.961 A delivers 0.961 C of charge in one single second. It will take
to transfer all these charge and deposit 0.500 g of Co.
Answer: 448 g of will be required to completely react with 784g moles of CO(g) during this reaction.
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
2 moles of require = 1 mole of
Thus 28 moles of will require=
of
Mass of
Thus 448g of will be required to completely react with 784g moles of CO(g) during this reaction.