It seems to overall decrease.
*clink* a toast *clink* a toast *clink* a toast *clink* *clink*
Surface runoff, its quite obvious in the picture
<span>Step 1 is to determine the mass of each part
Mass of Ca is 40.08 g
Mass of C is 12.01 g
Mass of O is 16.00 x 3 = 48.00 g
Step 2 is to determine the total mass of the compound
Total mass of CaCO3 is 40.08 + 12.01 + 48.00 = 100.09 g
Step 3 is to determine the % of each part using the following formula:
Mass of part / total mass x 100 =
40.08 / 100.09 x 100 = 40.04 % Ca
12.01 / 100.09 x 100 = 12.00 % C
48.00 / 100.09 x 100 = 47.96 % O
Step 4 is to double check by adding all percentages. If they equal 100, then I probably did it right. :)
40.04
+12.00
+47.96
=100.00</span><span>
</span>
Answer:
142240
Explanation:
We are told in the question:
Height of Gateway Arch in St. Louis, MO = 630ft
We are asked, how many U.S. dimes would be in a stack of the same
height when 1 dime is 1.35 mm thick.
Step 1
Convert height in ft to mm
1 ft = 304.8 mm
630ft =
Cross Multiply
630ft × 304.8mm/1ft
= 192024 mm.
Step 2
To find how many US dimes would be in a stack of the same height
= Total thickness/ Thickness of 1 US dime
= 192024 mm/1.35mm
= 142240
Therefore, the number of dimes that would be in a stack of the same
height is 142240
