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mylen [45]
3 years ago
5

What is the minimum horizontal force needed to make the box start moving? The coefficients of kinetic and static friction betwee

n the box and the floor are .24 and .41
Physics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

minimum horizontal force required to start the block motion is F = 0.41 mg

Explanation:

As we know that box is placed on the horizontal floor

so here the normal force on the box is counter balanced by the weight of the box

so we will have

F_n = mg

now in order to displace the box from its position we need to apply the external force which will just exceed the limiting static friction force

So here we will have

F_s = \mu_s F_n

here we know that

\mu_s = 0.41

F_s = 0.41(mg)

so minimum horizontal force required to start the block motion is F = 0.41 mg

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A flat sheet of ice has a thickness of 1.4 cm. It is on top of a flat sheet of crown glass that has a thickness of 3.0 cm. Light
MAXImum [283]

Answer:

t = 2.13 10-10 s , d = 6.39 cm

Explanation:

For this exercise we use the definition of refractive index

        n = c / v

Where n is the refraction index, c the speed of light and v the speed in the material medium.

The refractive indices of ice and crown glass are 1.13 and 1.52, respectively, therefore the speed of the beam in the material medium is

        v = c / n

As the beam strikes perpendicularly, the beam path is equal to the distance of the leaves, there is no refraction, so we can use the uniform motion relationships

        v = d / t

        t = d / v

        t = d n / c

Let's look for the times on each sheet

Ice

        t₁ = 1.4 10⁻² 1.31 / 3 10⁸

        t₁ = 0.6113 10⁻¹⁰ s

Crown glass (BK7)

        t₂ = 3.0 10⁻² 1.52 / 3.0 10⁸

        t₂ = 1.52 10⁻¹⁰ s

Time is a scalar therefore it is additive

         t = t₁ + t₂

         t = (0.6113 + 1.52) 10⁻¹⁰

         t = 2.13 10-10 s

The distance traveled by this time in a vacuum would be

        d = c t

       d = 3 10⁸ 2.13 10⁻¹⁰

       d = 6.39 10⁻² m

       d = 6.39 cm

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If distance between two charges increased by 2 times then force
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Answer:

4. B and D

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Two points along a transverse wave (such as the one in the figure) are said to be in phase when:

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Basically, we say that two points are in phase when they are separated by a complete cycle (one complete oscillation) of the wave.

For this wave, we see that point B and C have same displacement, but they are not in phase since in B the oscillation is going down while in C is going up.

Instead, B and D are in phase, because they are separated by one complete cycle: both points have same displacement and the oscillation is going in the same way for both of them.

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PLS HELP ME AS QUICK AS POSSIBLE,

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