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vlabodo [156]
4 years ago
12

What is the force experienced when a 5.0 kg mass is accelerated at 7.5 m/s??

Physics
1 answer:
Fittoniya [83]4 years ago
4 0

Answer:

F = 37.5 N

Explanation:

It is given that,

Mass of the object is 5 kg

Acceleration of the object is 7.5 m/s²

We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,

F = m

F=5\times 7.5\\\\F=37.5\ N

So, the force acting on the object is 37.5 N.    

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J-s. If your 1400-kg car is parked in an 8.54-m-long garage, what is the uncertainty in its velocity? cm/s the tolerance is +/-2
IgorC [24]

Answer:

\Delta v = 4.41 \times 10^{-37} cm/s

Explanation:

As per Heisenberg's uncertainty principle we know that

\Delta P \times \Delta x = \frac{h}{4\pi}

so here we have

\Delta P = m\Delta v

\Delta x = 8.54 m

now from above equation we have

m\Delta v \times (8.54) = \frac{h}{4\pi}

1400(\Delta v) \times (8.54) = \frac{6.626 \times 10^{-34}}{4\pi}

\Delta v = 4.41 \times 10^{-39} m/s

\Delta v = 4.41 \times 10^{-37} cm/s

8 0
3 years ago
Gravity is affected by
mrs_skeptik [129]

Gravity is affected by mass and distance

3 0
4 years ago
Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and th
Mariulka [41]

Answer:

a) 0.0288 grams

b) 2.6*10^{-10} J/kg

Explanation:

Given that:

A typical human  body contains about 3.0 grams of Potassium per kilogram of body mass

The abundance  for the three isotopes are:

Potassium-39, Potassium-40, and Potassium-41 with abundances are 93.26%, 0.012% and 6.728% respectively.

a)

Thus; a person with a mass of 80 kg will posses = 80 × 3 = 240 grams of potassium.

However, the amount of potassium that is present in such person is :

0.012% × 240 grams

= 0.012/100 × 240 grams

= 0.0288 grams

b)

the effective dose (in Sieverts) per year due to Potassium-40 in an 80- kg body is calculate as follows:

First the Dose in (Gy) = \frac{energy \ absorbed }{mass \ of \ the \ body}

= \frac{1.10*10^6*1.6*10^{-14}}{80}

= 2.2*10^{-10} \ J/kg

Effective dose (Sv) = RBE × Dose in Gy

Effective dose (Sv) =  1.2  *2.2*10^{-10} \ J/kg

Effective dose (Sv) = 2.6*10^{-10} J/kg

 

5 0
4 years ago
Vector A has a magnitude of 8.0 m and points 30 degrees north of east; vector B has a magnitude of 6.0 m and points 30 degrees w
liubo4ka [24]
D I believe it is hope it woke
5 0
3 years ago
15.6 grams of lead(II) nitrate is in a test tube. A 4.8-g sample of potassium iodide is an Erlenmeyer flask. The substance in th
miv72 [106K]

<u>Answer:</u>

 Mass of combined products = 20.4 grams

 Mass of combined product and Erlenmeyer flask = 136 grams

<u>Explanation:</u>

  By law of mass conservation, mass cannot be destroyed or created. So mass before reaction is mass after reaction.

  Mass of  lead(II) nitrate  = 15.6 grams

  Mass of potassium iodide = 4.8 grams

  Mass of the Erlenmeyer flask = 115.6 grams

  Mass of reactants = 15.6 + 4.8 = 20.4 grams

  So mass of products = 20.4 grams

  Mass of combined product and Erlenmeyer flask = 115.6 + 20.4 = 136 grams

6 0
3 years ago
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