Answer:
hmmm i dont know....
Explanation:
i just wanted free point. TANKS YOU SIR!!
From Carnot's theorem, for any engine working between these two temperatures:
efficiency <= (1-tc/th) * 100
Given: tc = 300k (from question assuming it is not 5300 as it seems)
For a, th = 900k, efficiency = (1-300/900) = 70%
For b, th = 500k, efficiency = (1-300/500) = 40%
For c, th = 375k, efficiency = (1-300/375) = 20%
Hence in case of a and b, efficiency claimed is lesser than efficiency calculated, which is valid case and in case of c, however efficiency claimed is greater which is invalid.
Newton taught us that Force = (mass) x (acceleration)
Force = (0.2) x (20) = <em>4 newtons</em> .
Something to think about: The ball can only accelerate while the club-face
is in contact with it. Once the ball leaves the club, it can't accelerate any more,
because the force against it is gone.
<span>37.589C
For gas laws, temperatures must be converted to Kelvin:
20C + 273.15 = 293.15K
The balloon assures that the mass of the gas remains the same and the problem states that the pressure of the gas remains the same. This means that a 6% change in volume corresponds to a 6% change in temperature. From this we calculate
293.15K * 1.06 = 310.739K
converting back to C
310.739 - 273.15 = 37.589C</span>
