All categories

4 years ago

What is the force experienced when a 5.0 kg mass is accelerated at 7.5 m/s??

Physics

1 answer:

Fittoniya [83]4 years ago

4 0

Answer:

F = 37.5 N

Explanation:

It is given that,

Mass of the object is 5 kg

Acceleration of the object is 7.5 m/s²

We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,

F = m

$F=5\times 7.5\\\\F=37.5\ N$

So, the force acting on the object is 37.5 N.

You might be interested in

J-s. If your 1400-kg car is parked in an 8.54-m-long garage, what is the uncertainty in its velocity? cm/s the tolerance is +/-2

IgorC [24]

Answer:

$\Delta v = 4.41 \times 10^{-37} cm/s$

Explanation:

As per Heisenberg's uncertainty principle we know that

$\Delta P \times \Delta x = \frac{h}{4\pi}$

so here we have

$\Delta P = m\Delta v$

$\Delta x = 8.54 m$

now from above equation we have

$m\Delta v \times (8.54) = \frac{h}{4\pi}$

$1400(\Delta v) \times (8.54) = \frac{6.626 \times 10^{-34}}{4\pi}$

$\Delta v = 4.41 \times 10^{-39} m/s$

$\Delta v = 4.41 \times 10^{-37} cm/s$

8 0

3 years ago

Gravity is affected by

mrs_skeptik [129]

Gravity is affected by mass and distance

3 0

4 years ago

Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and th

Mariulka [41]

Answer:

a) 0.0288 grams

b) $2.6*10^{-10} J/kg$

Explanation:

Given that:

A typical human body contains about 3.0 grams of Potassium per kilogram of body mass

The abundance for the three isotopes are:

Potassium-39, Potassium-40, and Potassium-41 with abundances are 93.26%, 0.012% and 6.728% respectively.

Thus; a person with a mass of 80 kg will posses = 80 × 3 = 240 grams of potassium.

However, the amount of potassium that is present in such person is :

0.012% × 240 grams

= 0.012/100 × 240 grams

= 0.0288 grams

the effective dose (in Sieverts) per year due to Potassium-40 in an 80- kg body is calculate as follows:

First the Dose in (Gy) = $\frac{energy \ absorbed }{mass \ of \ the \ body}$

= $\frac{1.10*10^6*1.6*10^{-14}}{80}$

= $2.2*10^{-10} \ J/kg$

Effective dose (Sv) = RBE × Dose in Gy

Effective dose (Sv) = $1.2 *2.2*10^{-10} \ J/kg$

Effective dose (Sv) = $2.6*10^{-10} J/kg$

5 0

4 years ago

Vector A has a magnitude of 8.0 m and points 30 degrees north of east; vector B has a magnitude of 6.0 m and points 30 degrees w

liubo4ka [24]

D I believe it is hope it woke

5 0

3 years ago

15.6 grams of lead(II) nitrate is in a test tube. A 4.8-g sample of potassium iodide is an Erlenmeyer flask. The substance in th

miv72 [106K]

<u>Answer:</u>

Mass of combined products = 20.4 grams

Mass of combined product and Erlenmeyer flask = 136 grams

<u>Explanation:</u>

By law of mass conservation, mass cannot be destroyed or created. So mass before reaction is mass after reaction.

Mass of lead(II) nitrate = 15.6 grams

Mass of potassium iodide = 4.8 grams

Mass of the Erlenmeyer flask = 115.6 grams

Mass of reactants = 15.6 + 4.8 = 20.4 grams

So mass of products = 20.4 grams

Mass of combined product and Erlenmeyer flask = 115.6 + 20.4 = 136 grams

6 0

3 years ago