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Georgia [21]
4 years ago
13

The distance from the Moon to Earth is 5.46 * 108 km. How long does it take a laser need to travel between the moon and earth?

Chemistry
1 answer:
Gennadij [26K]4 years ago
8 0

Answer:

B. 1.82(10³) seconds (1820 seconds)

Explanation:

Speed of Light: 3.00(10⁸) m/s or 3.00(10⁵) km/s

We know the distance from the Moon to Earth as 5.46(10⁸) km

We simply divide the distance by the speed of light:

\frac{5.46(10^8)}{3.00(10^5)}

We should get 1820 seconds or B. 1.82(10³) as our answer.

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How many electrons in an atom could have these sets of quantum numbers? n=2, n=4 l=1, n=6 l=2 m_l=-1?
Katena32 [7]
When n=2 we have 8electrons, when n=4 l=1 we have 6electrons, when n=6 l=2 m-l=-1 qe have 1electron
6 0
3 years ago
If it takes 7,529 calories of heat to warm 750.0 grams of water, what was the temperature change? The specific heat of water in
Zigmanuir [339]

Answer:

The temperature change was 10.04 °C.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system. In this way, there is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case you know:

  • Q= 7,529 calories (cal)
  • c= 1 \frac{cal}{g*C}
  • M=750 grams

Replacing:

7,529 cal= 1  \frac{cal}{g*C} *750 g* ΔT

Solving you get:

ΔT=\frac{7,529 cal}{1 \frac{cal}{g*C}*750 g }

ΔT= 10.04 °C

So, <u><em>the temperature change was 10.04 °C.</em></u>

6 0
3 years ago
Read 2 more answers
Heating gas to create plasma can yield
topjm [15]
Hey there, The answer is A. Free electrons.
4 0
3 years ago
Lipids that are liquid at room temperature are called oils <br> a. True <br> b. False
erica [24]
The answer to your question is false.
4 0
4 years ago
The second-order rate constant for the following gas-phase reaction is 0.041 1/MLaTeX: \cdotâs. We start with 0.438 mol C2F4 in
pantera1 [17]

Answer:

134.8 seconds is the half-life (in seconds) of the reaction for the initial C_2F_4 concentration

Explanation:

Half life for second order kinetics is given by:

t_{\frac{1}{2}=\frac{1}{k\times a_0}

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

t_{\frac{1}{2} = half life

k = rate constant

a_0 = initial concentration

a = Final concentration of reactant after time t

We have :

C_2F_4 \longrightarrow \frac{1}{2} C_4F_8

Initial concentration of C_2F_4=[a_o]=\frac{0.438 mol}{2.42 L}=0.1810 mol/L

Rate constant = k = 0.041 M^{-1} s^{-1}

t_{\frac{1}{2}=\frac{1}{k\times a_0}

=\frac{1}{0.041 M^{-1} s^{-1}\times 0.1810 mol/L}

t_{1/2}=134.8 s

134.8 seconds is the half-life (in seconds) of the reaction for the initial C_2F_4 concentration

3 0
3 years ago
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