The atomic mass of an atom if its mass is approximately equal to carbon-12 will be 12 and in case of 4.5 times carbon-12 will be 54
Atomic mass of an element is the average mass of the atoms of an element which are measured in atomic mass unit. Or we can also say that the atomic mass is actually the weighted mass is a weighted average of all of the isotopes of elements, in which the mass of each element is multiplied by the abundance of that particular isotope.
So the atomic mass of an atom if the mass is approximately equal to carbon-12 then the mass of the element will be equal to 12 as the atomic mass of carbon-12 is 12.
where as the atomic mass of an atom if its mass is approximately equal to 4.5 times as much as carbon-12 will be ⇒ 4.5×12= 54
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The answer to this question is 5
B. False
When the maximum amount of solute has been dissolved in a given amount of solvent, we say that the solution is saturated with solute.
The scientific models are used because they allow scientists to make predictions and make it easier for scientists to avoid using data. option A and C is correct.
<h3>What are scientific models?</h3>
The scientific models are those which is given by scientists to allow them to make prediction about anything particular on which they are working or making research for it some examples are plum pudding model for an atom and bohr's model of an atom etc.
The biggest advantage is that scientists do not have to check the given data which are written into books they can perform their experiment and can conclude the data by performing experiment.
Therefore, scientific models are used because they allow scientists to make predictions and make it easier for scientists to avoid using data. option A and C is correct.
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Answer:
4.96E-8 moles of Cu(OH)2
Explanation:
Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.
Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.
![pH= -log[H]\\pH= -log (\frac{kw}{[OH]})](https://tex.z-dn.net/?f=pH%3D%20-log%5BH%5D%5C%5CpH%3D%20-log%20%28%5Cfrac%7Bkw%7D%7B%5BOH%5D%7D%29)
![8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}](https://tex.z-dn.net/?f=8.23%20%3D%20-%20log%28%5Cfrac%7BKw%7D%7B%5BOH%5D%7D%20%5C%5C10%5E%7B-8.23%7D%20%3D%20Kw%2F%5BOH%5D%5C%5C%20%5BOH%5D%20%3D%20Kw%2F10%5E%7B-8.23%7D)
![[OH]=1.69E-6](https://tex.z-dn.net/?f=%5BOH%5D%3D1.69E-6)
This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:
In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":
The expression for Kps is:
![Kps= [Cu^{2+}] [OH]^2](https://tex.z-dn.net/?f=Kps%3D%20%5BCu%5E%7B2%2B%7D%5D%20%5BOH%5D%5E2)
The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.
"s" is the soluble quantity of Cu(OH)2.
The solution for this third grade equation is 
Now, let us calculate the moles in 1 L:
