Answer:
The vapor pressure in solution is 0,0051 atm
Explanation:
This is the formula for vapor pressure lowering, the colligative property.
P vapor = Pressure sv pure . Xsv
Where Xsv is data.
Xsv means Molar fraction (moles solvent/total n° moles)
Vapor pressure of water, pure is 17.5 mmHg
P vapor = 0,0313 atm . 0163
P vapor in solution = 0,0051 atm
Molar fraction does not have units
A solution will have less vapor pressure than that observed in the pure solvent.
Answer:
hmmmm
Explanation: Balance the reaction of KOH + H3PO4 = K3PO4 + H2O using this chemical equation balancer!
Answer:
C2H4Cl2
Explanation:
Firstly, we know that the compound contains only three elements. These are carbon, hydrogen and oxygen. We have the percentage compositions of carbon and hydrogen, thus we need the one for chlorine. To get the one for chlorine, we simply subtract that of carbon and hydrogen from a total of 100%.
Hence percentage composition of chlorine = 100 - 24.27 - 4.07 = 71.66%
Now, we divide the percentage compositions by the atomic masses. The atomic masses of carbon, hydrogen and chlorine are 12, 35.5 and 1 respectively. We go on to the divisions as follows.
C = 24.27/12 = 2.0225
H = 4.07/1 = 4.07
Cl = 71.66/35.5 = 2.02
We then go on to divide each by the smallest which is 2.02
C = 2.0225/2.02 = 1
H = 4.07/2.02 = 2
Cl = 2.02/2.02 = 1
Hence the empirical formula is CH2Cl
Now, since the molecular mass is 98.95, we need to calculate the molecular formula
Hence, [CH2Cl]n = 98.95
[12 + 2(1) + 35.5]n = 98.95
[12 + 2 + 35.5]n = 98.95
49.5n = 98.95
n = 98.95/49.5 = 2
The molecular formula is thus [CH2Cl]2 = C2H4Cl2
Explanation:
Hello, let's observe the given data first. The data says The conc of magnesium chloride solution is 0.117 mol/L that means in one litre solution 0.117 mole MgCl2 are present. but we have to find the moles of magnesium chloride, magnesium ions & chloride ions in 16.4 mL solution.
Now 16.4 ml solution contains 1.91× 10-³ magnesium chloride.
Before finding the amount of ions in solution let's have a look at dissociation of magnesium chloride.
<em>One mole of Magnesium chloride produces 1 mole of magnesium & 2 mole of chloride ions.</em>
Hence 1.91× 10-³ moles of magnesium chloride will produce 1.91 × 10-³ moles of magnesium ion & 3.82 × 10-³ moles of chloride ions.
Answer:
The metallic oxide is Li₂O
Explanation:
Let the metallic oxide be M₂O
Thus;
M₂O + H₂ = 2M + H₂O
Molar mass of M₂O = (2x + 16)
We assume Molar mass of M to be x.
We are told that 5.00 g of the metallic oxide produces 2.32 g of the metal.
By proportion, we can write the following;
5g of M₂O × (1 mole of M₂O/(2x + 16)) × (2 moles of M/1 mole of M₂O) = 2.32 g of M × 1 mole of M/x g of M
This cancels out to give us;
10/(2x + 16) = 2.32/x
Cross multiply to get;
10x = 2.32(2x + 16)
10x = 4.64x + 37.12
10x - 4.64x = 37.12
5.36x = 37.12
x = 37.12/5.36
x = 6.925 g/mol
The metal with a molar mass closest to this value of x is Lithium which has a molar mass of 6.94 g/mol
Thus the metal is Lithium and as such the metallic oxide is Li₂O
