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4 years ago

tickets are on sale for one year pass to an adventure park. each ticket sells for $65.50. What is the equation

Mathematics

1 answer:

kykrilka [37]4 years ago

6 0

Y=65.5x this is the equation

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a conference will take place in a large hotel meeting room. The organizers of the conference have created a drawing to determine

Bogdan [553]

Answer:

313 ft

Step-by-step explanation:

If 12in = 12 ft

313in = x

= 313 ft

4 0

3 years ago

Help please?

Alla [95]

$\bf \begin{array}{clclll}
3^{1001}&\qquad &4^{1002}\\
\uparrow &&\uparrow \\
a&&b
\end{array}\\\\
-----------------------------\\\\
(a+b)^2-(a-b)^2\implies (a^2+2ab+b^2)-(a^2-2ab+b^2)
\\\\\\
a^2+2ab+b^2-a^2+2ab-b^2\implies 2ab+2ab\implies 4ab
\\\\\\
now\qquad 4(3^{1001})(4^{1002})=k12^{1001}\qquad 
\begin{cases}
12^{1001}\\
(4\cdot 3)^{1001}\\
4^{1001}\cdot 3^{1001}
\end{cases}$

$\bf \\\\\\
4(3^{1001})(4^{1002})=k(4^{1001}\cdot 3^{1001})\implies \cfrac{4(3^{1001})(4^{1002})}{4^{1001}\cdot 3^{1001}}=k
\\\\\\
4\cdot \cfrac{3^{1001}}{3^{1001}}\cdot \cfrac{4^{1002}}{4^{1001}}=k\implies 4\cdot 4^{1002}4^{-1001}=k\impliedby 
\begin{array}{llll}
\textit{same base}\\
\textit{add the}\\
exponents
\end{array}
\\\\\\
4\cdot 4^{1002-1001}=k\implies 4\cdot 4^1=k\implies 16=k$

6 0

4 years ago

The president of the student council wants to survey the student population about parking. She decides to take a random sample o

iren2701 [21]

Answer:

Should be (B)

01-1020

ED2021

6 0

3 years ago

What is the rate of change between the points (0,0) and (2,100)?

xxMikexx [17]

I think you can google this

7 0

3 years ago

Read 2 more answers

Lenmana started studying how the number of branches on her tree grows over time. The number of branches increases by a factor of

Ad libitum [116K]

Answer:

$N(t) = 48 * 11/6^{\frac{t}{3.5} }$

Step-by-step explanation:

The formula for <u>exponential growth</u> is y = ab^x.

To write this equation, we know it has to start with 48 (which is the variable a). We need to add the rate of growth. This is 11/6 (which is variable b). But we also need to account for the "every 3.5 years" part, so divide the x as an exponent by 3.5.

N(t) = 48 * 11/6^(t/3.5)

This equation is easy to test, and it's a good idea to test it after you write it. For example, after 3.5 years we know that it should have 48*11/6 branches. Does our equation work? Yes.

7 0

3 years ago