The answer to this is letter D.
Chromium's electron configuration is <span>1s2 2s2 2p6 3s2 3p6 3d5 4s1, where the last electron is in the s orbital with only 1. As for Li, it is found in the group 1 metals, and it is a fact that all elements under this group has the their last electron to be in the s orbital with only one electron in their outermost shell.
</span>The electron configuration<span> associated with the lowest energy level of the atom is referred to as </span>ground state and each electron ion is in the lowest energy level possible. When the moment comes that electrons go into a higher level of energy, that is what we call the excited state.
Answer:
1. 1.25 mol ants x 6.02*10^23 ants/1 mol ants = 7.53*10^23 ants
2. 4.92*10^26 pencils x 1 mol pencils/6.02*10^23 pencils = 817 mol pencils
3. 0.26 mol molecules x 6.02*10^23 molecules/1 mol molecules = 1.6*10^23 molecules
4. 3.46*10^19 molecules x 1 mol molecules/6.02*10^23 molecules = 5.75*10^-5 mol molecules
5. 5.3*10^20 atoms x 1 mol atoms/6.02*10^23 atoms = 8.8 mol atoms
6. 0.11 mol atoms x 6.02*10^23 atoms/1 mol atoms = 6.6*10^22 atoms
I would suggest looking into "dimensional analysis" for help with this type of material. Dimensional analysis will stick with you all throughout chemistry, so picking it up will be extremely beneficial.
Answer:
N2 is lost from the craft 6.9% faster than O2 is lost.
Explanation:
<u>Step 1:</u> Data given
0.500 atm of N2
0.500 atm of 02
Molar mass of 02 = 2*16 g/mole = 32 g/mole
Molar mass of N2 = 2* 14 g/mole = 28g/mole
<u>Step 2:</u> Calculate the rate of loss
r1N2 / r2O2 = √(M2(02)/M1(N2)) = √(32/28) = 1.069
1.069-1)*100= 6.9%
This means N2 is lost from the craft 6.9% faster than O2 is lost.
Keep trying you will get if you keep trying ok
155.9
Explanation:
A flask containing 9.65 mL of liquid has a mass of 164.5g. The empty flask has a mass of 155.9
