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Murljashka [212]
3 years ago
6

Which is a way that the elements are groupef on the periodic table

Chemistry
1 answer:
hammer [34]3 years ago
8 0
Your answer is B because elements within the same column have equal numbers of valence electrons which determines the reactivity of an element. 
You might be interested in
________ is the enthalpy change when 1 mole of water is produced by the reaction of an acid and a base under standard conditions
Tatiana [17]

Standard enthalpy change of neutralization is the enthalpy change when 1 mole of water is produced by the reaction of an acid and a base under standard conditions.

Enthalpy change of neutralization:

  • Every time enthalpy change of neutralization is calculated, one mole of water is produced.
  • Heat is released when an acid and an alkali react, hence enthalpy changes of neutralization are always negative.
  • The values are always quite comparable for reactions involving strong acids and alkalis, falling between -57 and -58 kJ mol-1.
  • If the reaction is the same in each case of a strong acid and a strong alkali, the enthalpy change is similar.

Learn more about the Enthalpy of neutralization with the help of the given link:

brainly.com/question/15347368

#SPJ4

7 0
2 years ago
Calculate the formula mass for the compound tin(IV) sulfate.
stellarik [79]
The molecular formula for tin(IV)  sulfate is Sn(SO₄)₂.
mass of sulfur S = 32.065
as there is 2 sulfur in tin (IV) sulfate = 32.065 x 2 = 64.13
mass of oxygen = 15.999 and there are 8 oxygen atoms in the formula; 
8 x 15.999 = 127.992
mass of tin = 118.71
now add all the masses = 64.13 + 127.992 + 118.71 = 310.832 
formula mass of tin(IV) sulfate is 310.832
7 0
3 years ago
Which substance can act as an Arrhenius base in an aqueous solution
miss Akunina [59]
An Arrhenius base is a substance that are being dissolves in water dissociate and gives Hydroxide ions. (OH⁻) 
7 0
3 years ago
A compound sample contains 60.87% c, 4.38% h, and 34.75% o by mass. it has a molar mass of 276.2 g/mol. what are the empirical a
Allushta [10]

Step 1) Assume we have 100 grams of the compound. Thus, we're starting with 60.87 grams C, 4.38 grams H, and 34.75 grams O.

Step 2) Convert the masses of each to moles.

60.87 grams C=5.068276436 mol C

4.38 grams H=4.345238095 mol H

34.75 grams O=2.171875 mol O

step 3) Determine your simplest whole-number ratio of moles by dividing each number of moles by the smallest number of moles. (In this case, the smallest number of moles is 2.171875 mol O)

O: \frac{2.171875}{2.171875} = 1

H:\frac{4.345238095}{2.171875} = 2

C: \frac{5.068276436}{2.171875} = 2.33

Step 4) Whenever you're doing an empirical formula problem, and you run into a number that ends with .33, rather than rounding down to a whole number, you need to multiply all your ratios by 3 to obtain whole numbers. Thus, you will get:

O=3

H=6

C=7

Step 5) write the empirical formula using the ratios.

The empirical formula is: C₇H₆O₃

Step 6) The subscripts in the molecular formula of a substance are always whole-number multiples of the subscripts in its empirical formula. This multiple is found by dividing the molecular weight (which was given to us in the problem: 276.2 amu) by the empirical formula weight (C₇H₆O₃ =138.118 amu).

\frac{276.2}{138.118} = 2

Step 7) simply multiply the subscripts in the empirical formula by the multiple, 2, and you will get the molecular formula.

The molecular formula is: C₁₄H₁₂O₆

6 0
3 years ago
What classification should this reaction have? CaC12 + F2 = CaF2 + CI2
Sedbober [7]

Answer:

Single-Replacement Reaction

General Formulas and Concepts:

<u>Types of Reactions</u>

  • Synthesis Reactions: A + B → AB
  • Decomposition Reactions: AB → A + B
  • Single-Replacement Reactions: A + BC → AB + C
  • Double-Replacement Reactions: AB + CD → AD + BC

Explanation:

<u>Step 1: Define reaction</u>

CaCl₂ + F₂ → CaF₂ + Cl₂

<u>Step 2: Identify backplate</u>

Single-Replacement Reactions: A + BC → AB + C

BC = CaCl₂

A = F₂

AB = CaF₂

C = Cl₂

7 0
3 years ago
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