All categories

3 years ago

What is the molarity of an H2SO4 solution if 49.0 mL are titrated by 68.4 mL of a .333 M NaOH solution

Chemistry

1 answer:

denis23 [38]3 years ago

8 0

Answer:

0.232M

Explanation:

H2SO4+2NaOH--> 2H2O+Na2SO4

(0.0684L)(.333M NaOH) = 0.0227 moles NaOH (1 mol H2SO4/2 mol NaOH)

= 0.0114 moles H2SO4

M = 0.0114 moles/ 0.0490L solution = 0.232M

* Please text me at 561-400-5105 for tutoring: I can do assignments, labs, exams, etc. :)

You might be interested in

The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when

Natasha_Volkova [10]

Answer: 0.52V

Explanation:

Ecell = Ecell(standard) - [(0.0592 logQ)/n]

Q = product of the quotient

n = no of electrons transferred = 2

Ecell = 0.63 - [(0.0592*Log(1 / 2.0 * 10-4) / 2]

Ecell = 0.63 - 0.0194

Ecell = 0.5205V

5 0

3 years ago

Which is an example of a chemical change

jonny [76]

The answer is baking a cake.

4 0

3 years ago

Read 2 more answers

Oxidation of methane

Mandarinka [93]

<h2><em><u>ᎪꪀsωꫀᏒ</u></em></h2>

➪Methane (CH4) is oxidized with molecu- lar oxygen (O2) to carbon dioxide (CO2).

4 0

3 years ago

Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

$n_{(AcO)_2Cu} = 0.0053515 mol$

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

$c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M$

8 0

4 years ago

What is usually needed to help a decomposition reaction occur

ArbitrLikvidat [17]

<u>The addtion of energy</u> <span>is usually needed to help a decomposition reaction occur</span>

3 0

3 years ago

Read 2 more answers