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Vsevolod [243]
1 year ago
14

What would the hydroxide ion concentration be if the hydrogen ion concentration was 1 x 10-3 M?

Chemistry
1 answer:
Sonbull [250]1 year ago
3 0

Answer:

1 x 10⁻¹¹ M

Explanation:

<u>(Step 1)</u>

Determine the pH.

pH = -log[H⁺]

pH = -log[1 x 10⁻³ M]

pH = 3

<u>(Step 2)</u>

Determine the pOH.

pH + pOH = 14

3 + pOH = 14

pOH = 11

<u>(Step 3)</u>

Determine the hydroxide (OH⁻) concentration.

[OH⁻] = 10^-pOH

[OH⁻] = 10⁻¹¹

[OH⁻] = 1 x 10⁻¹¹ M

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In the laboratory, a student adds 50.4 mL of water to 16.5 mL of a 0.880 M hydroiodic acid solution. What is the concentration o
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Compute the molar enthalpy of combustion of glucose (C6 H12O6 ): C6 H12O6 (s) + 6 O2 (g) → 6 CO2 (g) + 6 H2 O (g) Given that com
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Answer:

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Explanation:

Step 1: Data given

Mass of glucose = 0.305 grams

Combustion of 0.305 grams causes a raise of 6.30 °C

Calorimeter has a heat capacity of 755 J/°C

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Step 2: The balanced equation

C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (g)

Step 3:

ΔH = (m * C * ΔT + c(calorimeter) * ΔT)

with m = mass of the solutin = 0.305 grams

with C = heat capacity of water = 4.184 J/g°C

with ΔT = the change in temperature = 6.30 °C

with c(calorimeter) = 755 J/°C

ΔH = 0.305 * 4.184 *6.30 + 755 * 6.30  = 4764.5 J ( negative because it's exothermic)

Step 4: Calculate moles of glucose

Moles glucose = mass glucose / Molar mass glucose

Moles glucose = 0.305 grams / 180.2 g/mol

Moles glucose = 0.00169 moles

Step 5: Calculate molar enthalpy

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3 years ago
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Answer:

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