Question

Use the periodic table to find the charge of the ion that each atom is most likely to form. The charge of a sulfur (S) ion is The charge of a potassium (K) ion is The charge of a boron (B) ion is The charge of an iodine (I) ion is The charge of a bromine (Br) ion is

Answer 1

Explanation:

Elements that gain electrons will have a negative charge and elements that lose electrons will have a positive charge.

• Atomic number of sulfur (S) atom is 16 and its electronic distribution is 2, 8, 6. In order to completely fill its octet sulfur will gain 2 electrons and thus it forms $S^{2-}$ ion.

• Atomic number of potassium (K) atom is 19 and its electronic distribution is 2, 8, 8, 1. In order to stabilize its octet potassium will lose 1 electron and thus it forms $K^{+}$ ion.

• Atomic number of boron (B) atom is 5 and its electronic distribution is 2, 3. In order to stabilize its octet boron will lose 3 electrons and thus it forms $B^{+3}$ ion.

• Atomic number of iodine (I) atom is 53 and it has 7 valence electrons. In order to stabilize its octet iodine will gain 1 electron and thus it forms $I^{-}$ ion.

• Atomic number of bromine (Br) atom is 35 and it also has 7 valence electrons. In order to stabilize its octet bromine will gain 1 electron and thus it forms $Br^{-}$ ion.

Answer 2

S = -2, K = +1, B = +3, I = -1, Br = -1