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Anika [276]
2 years ago
7

Thermohaline circulation _______. a. supplies heat to polar regions b. causes salt lake formation c. causes oxbow lake formation

d. is unaffected by heat fluctuations Please select the best answer from the choices provided A B C
Chemistry
1 answer:
DerKrebs [107]2 years ago
7 0

Thermohaline circulation that occur in the ocean part that flows across sea surface help to supply heat to polar regions.

<h3>What is Thermohaline circulation?</h3>

The thermohaline circulation refer to a section and region of the ocean circulation which is majorly driven by heat gradient and freshwater that flows across the sea surface and also from the mixture of heat and salt that occur at the inside part of the ocean.

Therefore, Thermohaline circulation help to supply heat to polar regions.

Learn more about thermohaline circulation here.

brainly.com/question/1176119

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Gekata [30.6K]

Answer:

B

Explanation:

8 0
3 years ago
PLEASE HELP ME I BEG YOU
slamgirl [31]
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5 0
3 years ago
Read 2 more answers
How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?
Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

C_{6}H_{8}O_{6}

Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.

We have that:

C_{6}=12.0107g*6=72.08g\\\\H_{8}=1.008g*8=8.064g\\\\O_{6}=15.999g*6=95.994g\\\\C_{6}H_{8}O_{6}=72.08g+8.064g+95.994g=176.138g

To know the percent of each element, we need to to the following:

C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

5 0
3 years ago
A chemical indicator that changes colors depending on the concentration of h+ in the solution is called a
DanielleElmas [232]
Answer is: acid-base indicator or pH indicators.

Acid-base indicators are usually weak acids or bases and they are chemical<span> detectors for hydrogen or hydronium cations.</span>
Example for acid-base indicator is phenolphthalein (molecular formula C₂₀H₁₄O₄). Phenolphthalein is <span>colorless in </span>acidic<span> solutions and pink in </span>basic<span> solutions.
Another example is m</span><span>ethyl orange. It is red colour in acidic solutions and yellow colour in basic solutions.</span>

3 0
3 years ago
The ccl4 formed in the first step is used as a reactant in the second step. if 2.00 mol of ch4 reacts, what is the total amount
Leni [432]
<span>CH4 + 4 Cl2 → CCl4 + 4 HCl (4.00 mol CH4) x (1/1) x (0.70) = 2.80 mol CCl4 (4.00 mol CH4) x (4/1) x (0.70) = 11.2 mol HCl CCl4 + 2 HF → CCl2F2 + 2 HCl (2.80 mol CCl4) x (2/1) x (0.70) = 3.92 mol HCl 11.2 mol + 3.92 mol = 15.1 mol HCl from both steps</span>
8 0
3 years ago
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