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Arlecino [84]
4 years ago
9

PLEASE SOMEONE ANSWER THIS I ONLY HAVE 30 MINS

Physics
2 answers:
Liono4ka [1.6K]4 years ago
4 0

Explanation:

Observing the graph, we see that the object moves at a constant velocity of 3 m/s during the span of 6 to 8 seconds. We can thereby find displacement in the in this intreval by finding the area under the curve during 6 to 8 seconds (forming a rectangle).

Displacement (area of rectangle with length = 3 and breadth = 2) = 3 * 2 = <em><u>6 m</u></em>

kow [346]4 years ago
3 0

6 meters

Change in displacement = v times change in t .

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4 0
4 years ago
During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 6.22 s, how high does it rise? The accel
BigorU [14]

Answer:

47.4 m

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When an object is thrown upward, it rises up, it reaches its maximum height, and then it goes down. The time at which it reaches its maximum height is half the total time of flight.

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Now we consider only the downward motion of the ball: it is a free fall motion, so we can find the vertical displacement by using the suvat equation

s=ut+\frac{1}{2}gt^2

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g=9.8 m/s^2 is the acceleration of gravity (taking downward as positive direction)

Solving the  formula, we find

s=\frac{1}{2}(9.8)(3.11)^2=47.4 m

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