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CaHeK987 [17]
3 years ago
8

Select the correct expression that gives the block's acceleration at a displacement x from the equilibrium position. Note that x

can be either positive or negative; that is, the block can be either to the right or left of its equilibrium position.
a= -kx
a= kx
a= k/m x
a= -k/m x
Physics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer:

the correct is d

a= - k/m x

Explanation:

I got it correct

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4 0
3 years ago
Use the drop-down menus to complete the statement.
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8 0
3 years ago
Read 2 more answers
The mass of the Earth is 6 × 1024 kg, the mass of the Moon is 7 × 1022 kg, and the center-to-center distance is 4 × 108 m. How f
Karolina [17]

Answer:

The center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.

Explanation:

Let the reference point be the center of the Earth

X_{Cm = \frac{M_eX_e +M_mX_m}{M_e+M_m}

Where;

Xcm is the distance from center of the Earth =?

Me is the mass of the Earth = 6 × 10²⁴ kg

Xe is the center mass of the Earth = 0

Mm is the mass of the moon = 7 × 10²² kg

Xm is the center mass of the moon =  4 × 10⁸ m

X_{Cm = \frac{M_eX_e +M_mX_m}{M_e+M_m} =  \frac{M_e(0) +M_mX_m}{M_e+M_m} = \frac{ M_mX_m}{M_e+M_m}}\\\\X_C_m = \frac{7 X 10^{22}*4X10^8}{6X10^{24}+7X10^{22}} =\frac{28 X10^{30}}{607X10^{22}}\\\\  X_C_m = 4.613 X10^6 m

Therefore, the center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.

8 0
3 years ago
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