All categories

3 years ago

What is the expression for the calculation triple 4 and then add 7 times 7

Mathematics

2 answers:

Vesna [10]3 years ago

8 0

4^3+7(7) in my opinion or 4^3+7*7

krok68 [10]3 years ago

4 0

(4 x 3) + (7 x 7) is the expression

You might be interested in

PLEASE HELP FAST<br> SEE BELOW

Papessa [141]

From the table, you know that Jupiter is further away from the sun. So if you subtract the distance of the shorter one, which is Mars, from the distance of the longer one, which is Jupiter, you woould get the distance of Jupiter from Mars.

4.84 x 10^8 - 1.42 x 10^8
= (4.84 - 1.42) x 10^8
= 3.42 x 10^8

Therefore the distance is 3.42 x 10^8

Hope this helped, if you don't understand what I was doing in the working, you can just imagine substituting a = 10^8, things will make more sense. As for what I was talking about in the huge paragraph above, if you're confused you can also draw it out.

8 0

3 years ago

What are the factors of x^2 + 8x + 12?

expeople1 [14]

Answer:

(x+2)(x+6)

Step-by-step explanation:

that is the answer because math

8 0

3 years ago

Read 2 more answers

Tyrell says if you subtract 1 from a number you get an even number.he writes these two equations as examples. 3-1=2 11-1=10

Anna11 [10]

Answer:

No Tyrell is incorrect.

Step-by-step explanation:

Tyrell is incorrect because if you take any even number and subtract one from it you would get an odd number. For example take 20, if you do 20-1 then that would give you 19.

4 0

3 years ago

Someone please help me ASAP

valentina_108 [34]

Answer:

36.3 percent

Step-by-step explanation:

6 0

3 years ago

A survey of athletes at a high school is conducted, and the following facts are discovered: 13% of the athletes are football pla

nekit [7.7K]

Answer:

The probability that an athlete chosen is either a football player or a basketball player is 56%.

Step-by-step explanation:

Let the athletes which are Football player be 'A'

Let the athletes which are Basket ball player be 'B'

Given:

Football players (A) = 13%

Basketball players (B) = 52%

Both football and basket ball players = 9%

We need to find probability that an athlete chosen is either a football player or a basketball player.

Solution:

The probability that athlete is a football player = $P(A)= \frac{13}{100}=0.13$

The probability that athlete is a basketball player = $P(B)= \frac{52}{100}=0.52$

The probability that athlete is both basket ball player and football player = $P(A\cap B) = \frac{9}{100}=0.09$

We have to find the probability that an athlete chosen is either a football player or a basketball player $P(A\cup B)$ .

Now we know that;

$P(A\cup B)= P(A) + P(B) - P(A \cap B)\\\\P(A\cup B) = 0.13+0.52-0.09=0.56\\\\P(A\cup B) = \frac{0.56}{100}=56\%$

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.

5 0

4 years ago