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Kitty [74]
4 years ago
7

What is 5.4w+8.2=9.8w-2.8

Mathematics
1 answer:
Natasha_Volkova [10]4 years ago
4 0

Simplifying

5.4w + 8.2 = 9.8w + -2.8

Reorder the terms:

8.2 + 5.4w = 9.8w + -2.8

Reorder the terms:

8.2 + 5.4w = -2.8 + 9.8w

Solving

8.2 + 5.4w = -2.8 + 9.8w

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '-9.8w' to each side of the equation.

8.2 + 5.4w + -9.8w = -2.8 + 9.8w + -9.8w

Combine like terms: 5.4w + -9.8w = -4.4w

8.2 + -4.4w = -2.8 + 9.8w + -9.8w

Combine like terms: 9.8w + -9.8w = 0.0

8.2 + -4.4w = -2.8 + 0.0

8.2 + -4.4w = -2.8

Add '-8.2' to each side of the equation.

8.2 + -8.2 + -4.4w = -2.8 + -8.2

Combine like terms: 8.2 + -8.2 = 0.0

0.0 + -4.4w = -2.8 + -8.2

-4.4w = -2.8 + -8.2

Combine like terms: -2.8 + -8.2 = -11

-4.4w = -11

Divide each side by '-4.4'.

w = 2.5

Simplifying

w = 2.5

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Step-by-step explanation:

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A circle fountain has a radius of 9.4 feet . What's the fountains diamiter
boyakko [2]
<h3>Answer:</h3>

18.8 feet

<h3>Step-by-step explanation:</h3>

We are given;

Radius of the fountain is 9.4 feet

We are required to determine the diameter of the fountains

We need to know that the diameter of a circle is twice the radius of the circle.

That is;

Diameter = 2r

Therefore;

Diameter of the fountain = 2 × 9.4 feet

                                         = 18.8 feet

Thus, the diameter of the fountain is 18.8 ft

3 0
3 years ago
Leon read 5/7 of the pages in his book.He has 28 pages left to read.How many pages has he read already?
Fittoniya [83]
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4 X 5 = 20.

Therefore, Leon read 20 pages.
4 0
3 years ago
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5 0
3 years ago
What is the ratio of the area of the inner square to the area of the outer square?
Anastasy [175]

Answer:

\frac{(a-b)^2+b^2}{a^2}

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

=\sqrt{(a-b-0)^2+(0-b)^2}

=\sqrt{(a-b)^2+b^2}

Thus the area of the inner square = (side)²

=(\sqrt{(a-b)^2+b^2})^2

=(a-b)^2+b^2\text{ square cm}

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

=\sqrt{(a-0)^2+0^2}

=\sqrt{a^2}=a

Thus, the area of the outer square = (side)²

=a^2\text{ square cm}

Hence, the ratio of the area of the inner square to the area of the outer square

=\frac{(a-b)^2+b^2}{a^2}

4 0
3 years ago
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