For this case we have that if the line that passes through point z is perpendicular to line AB, it is fulfilled that:
We find the slope of AB:
We choose the points that go through AB:
(-2.4)
(0, -4)
So:
On the other hand, the point z is (0,2).
Then the cut point with the "y" axis is 2.
The equation of the line is:
We test the points:
(-4,1)
Is fulfilled
(1, -2)
It is not true
(2,0)
It is not true
(4,4)
It is not true
Answer:
Option A
Answer:
y = -1/3x + 7/3
Step-by-step explanation:
A line that is perpendicular to another line has the opposite reciprocal slope. That means we flip the slope of the original line and place a negative in front. Since the original slope is 3, the slope perpendicular is -1/3.
Now that we know the slope, and because they gave us a point on that line, we can create a line. Plug in the points and the slope into y = mx + b, to solve for b, the y-intercept.
3 = -1/3 (-2) + b
9/3 = 2/3 + b
7/3 = b
Now we can create a line in slope intercept form: y = -1/3x + 7/3
Here is Standard Form if needed: x + 3y = 7
The question is
A square and an equilateral triangle have equal perimeters. The area of the triangle is 2√3 sq<span>uare inches. What is the number of inches in the length of the diagonal of the square?
</span>
we know that
the area of an equilateral triangle is
applying the law of sines
A=(1/2)*b²*sin 60°-----> 2√3=(1/2)*b²*√3/2
(2√3)*(2/√3)=(1/2)*b²
4=(1/2)*b²
b²=8
b=√8 in
perimeter of the triangle=3*b-----> 3*√8 in
let
x----> the length side of the square
perimeter of the square=perimeter of the triangle
perimeter of the square=3*√8 in
and
perimeter of the square=4*x
4*x=3*√8
x=(3/4)*√8----> x=(3/2)*√2 in
find the diagonal of the square
applying the Pythagoras theorem
D²=x²+x²----> D²=2*x²----> D²=2*((3/2)*√2)²
D²=2*(9/4)*2
D²=9
D=3 in
the answer is
the number of inches in the length of the diagonal of the square is 3
1. she saves $6.75
2.40-2n=36
3.9+2*3-3*2=9
