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Answer:</h2><h2>
The probability of students who play both basketball and baseball = 
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Step-by-step explanation:
In a certain Algebra class,
The total number of students = 27 students
Let the students playing basketball be represented as A and baseball as B.
The students who play basketball, A= 11
The students who play basetball,B =9
The students who play neither sport, = 11
The students who play both basketball and baseball, = ?
By formula, P(AUB)=P(A)+P(B)-P(A∩B)
Substituting the values in the equation, we get
P(AUB) = 
P(AUB) = 
The probability of students who play both basketball and baseball = 