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vfiekz [6]
3 years ago
7

Describe the acceleration of your bicycle as you ride it from your home to the stoe

Chemistry
2 answers:
NikAS [45]3 years ago
4 0
You will probably need more info, but it is probably accelerating and moving from one place to the next
Andrej [43]3 years ago
3 0
The acceleration of your bicycle as you ride it from your home to the store changes. It can increase and decrease. Constanta acceleration does not occur because that means that you would have to always go at the same speed and end up going pas the store. Reducing speed is a way of acceleration in physics. When you reach it, you can calculate how much your velocity was average and see how changing your acceleration changed it.

Your answer is: A series of increases and decreases 

Have an amazing day mate!

Shoutout to @Greenleafable 
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3 years ago
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A _____________reaction mechanism involves loss of a leaving group, formation of a ________ followed by the removal of a proton
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Answer:

The correct answer is Option C (E1) and Option B (carbocation).

Explanation:

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Some other possibilities offered aren't relevant to the procedure outlined. So the above alternative is accurate.

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4 years ago
A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple
miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

\frac{V}{T}=const.

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where in this problem we have:

V_1=490 mL is the initial volume of the gas

T_1=-35.0^{\circ} + 273 = 238 K is the initial temperature

T_2=42.0^{\circ}+273=315 K is the final temperature

Solving for V2, we find the final volume of the gas:

V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL

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