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My name is Ann [436]
3 years ago
8

What is the one variable that is changed in the experimental group called? the placebo the independent variable the control grou

p the dependent variable
Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
4 0

Answer:

the independant variable

Explanation:

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A major component of gasoline is octane C8H18. When liquid octane is burned in air it reacts with oxygen O2 gas to produce carbo
Nady [450]

Answer:

0.054 moles of carbon dioxide will be produced

Explanation:

Step 1: Data given

Number of moles oxygen = 0.085 moles

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of carbon dioxide

For 2 moles octane we need 25 moles oxygen gas to produce 16 moles carbon dioxide gas and 18 moles water vapor

0.0544

For 0.085 moles O2 we'll have 16/25 * 0.085 = 0.054 moles CO2

0.054 moles of carbon dioxide will be produced

7 0
3 years ago
Which of the gas laws takes into account the forces of attraction between molecules based on the characteristics of the gas? *
Alika [10]
The answer is Boyle’s Law
5 0
3 years ago
The weak acid HA is 5 % ionized (dissociated) in a 0.35 M solution.
ddd [48]

Answer:idk

Explanation:of a 0.26 M triethylamine, (C2H5)3N, solution. ... 5. Predict if a decrease in temperature is favorable for the following reactions: (5 pts) a. H2O(s)

5 0
3 years ago
7. Although carbon's three isotopes are carbon-12, carbon-13, and carbon-14, its
Naddik [55]

Answer:

B

Explanation:

carbon 12 is most useful to humans

4 0
2 years ago
Determine the mass of water in kg, if 4300 cal of energy is placed in water, resulting in a temperature change to 101.0 oC from
Airida [17]

Answer:

0.5059kg

Explanation:

The heat absorbed for the water is determined using the equation:7

Q = C×m×ΔT

<em>Where Q is heat absorbed (4300cal)</em>

<em>C is specific heat (1cal/g°C)</em>

<em>m is the mass in grams</em>

<em>ΔT is change in °C (101.0°C - 92.5°C = 8.5°C)</em>

<em />

Replacing:

4300cal = 1cal/g°C×m×8.5°C

505.9g = m

In kg, the mass of water is:

<h3>0.5059kg</h3>

<em />

6 0
3 years ago
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