The reactivity of a metal is determined by these things.
Firstly, the number of electrons in the outer shell; the fewer the number of electrons in the outer shell, the more reactive the metal.
The number of electron shells also affects reactivity, the more electron shells there are, the more reactive the metal.
Answer:any substance which may be harmful to the environment or hazardous to your health if inhaled, ingested or absorbed through the skin.
Explanation:
The following reaction gives a product with the molecular formula C₄H₈O₂. The diagram of the structure of the product can be seen in the image attached below.
The reaction between C₂H₂(ONa)₂ and C₂H₄Br results in the formation of the product C₄H₈O₂ and 2NaBr.
This reaction undergoes an SN₂ mechanism since there is no stable carbocation formed. In the reaction -O⁻Na⁺ attacks the ortho position in C₂H₄Br to form C₄H₈O₂.
In SN₂ mechanism is a nucleophilic substitution reaction where one bond is formed while another one is broken simultaneously.
The mechanism for the reaction can be seen in the image attached below.
Learn more about nucleophilic substitution reaction here:
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Answer:
Explanation:
First digit of the 2p^3 gives you value of n, in this case its = 2, So, n= 2
Second alphabet gives you the value of l,
l=0 =s
l=1 =p
l=3=d
l=4=f
since "p" is the alphabet in 2p^3, so in your case lt shoudlbe = 1 right?
ml= -l to +l , that is -1, 0, +1
Ms= +1/2 or -1/2 alaways remains same foe evrything.