Solution:
Given:
Change in entropy of the system, ΔS = 12J/K
Temperature of the system, 
= 250K
Now, we know that the change in entropy of a system is given by the formula:
ΔS = 
Amount of heat added, ΔQ = 
ΔQ = 3000J
Answer:
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1: University Lecturer
2: Market Researcher
3: Marketing Consultant
Explanation
1: University Lecturer
I am very good student and have strong grip over different academic concepts, I always have stood first in my class. I always got Distinction in my college. Moreover, I am very good at giving presentation, theretofore, I definitely believe that I can perform very well in teaching at the university level.
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A. I believe, lmk if I’m right
The smallest area of each cable if the stress is not to exceed 90MPa in bronze is 43.6 mm² and 120MPa in steel is 32.7 mm².
<h3>What is normal stress?</h3>
If the direction of deformation force is perpendicular to the cross-sectional area of the body, the stress is called normal stress. Changes in wire length and body volume will be normal.
σ = P/A
Where, σ = Normal stress
P = Pressure
A = Area
1 Kg = 9.81 N
800 kg = 7848 N
Since the rod is half bronze and half steel
800 kg = 7848/2
= 3924 N
Pₙ = Fₙ = 3924 N [n = Bronze]
Pₓ = 3924 N [x = steel]
Given,
σₙ = 90MPa
σₓ = 120MPa
Aₙ = ?
Aₓ = ?
Aₙ = Pₙ/σₙ
Aₙ = 3924/90
Aₙ = 43.6 mm²
Aₓ = Pₓ/σₓ
Aₓ = 3924/120
Aₓ = 32.7 mm²
To know more about normal stress, visit:
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Answer:
c) Elevations
Explanation:
Elevations in pipe systems design provide the views necessary in presenting a pipe isometrics indicating the pipe length, wideness of a line and the height of a pipe.The drafts person obtains the true north coordinates in the desired points where the pipeline is to pass and determines the required vertical grade where all vertical measurements will be referred.
