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lisov135 [29]
3 years ago
8

If 25% of y is 30, what is 60% of y?

Mathematics
1 answer:
madam [21]3 years ago
5 0

Answer:

60% of Y is 72

Step-by-step explanation:

25% of Y is 30 so multiply 30 by 4 and you get 120. Multiply 120 by .60 and that leaves you with 72 as your answer.

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At a basketball​ game, a team made 54 successful shots. They were a combination of​ 1- and​ 2-point shots. The team scored 93 po
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17 one point shots and 39 two point shots were made

Solution:

Given that,

At a basketball​ game, a team made 56 successful shots

They were a combination of​ 1- and​ 2-point shots

Let "x" be the number of 1 point shots

Then, 56 - x is the number of two point shots

The team scored 95 points in all

Therefore,

1(number of 1 point shots) + 2(number of two point shots) = 95

x + 2(56 - x) = 95

x + 112 - 2x = 95

x = 112 - 95

x = 17

Then, number of two point shots = 56 - x = 56 - 17 = 39

Thus 17 one point shots and 39 two point shots were made

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2 years ago
How to find a slope of (-3,-3) and (5,9)
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Answer: m= 3/2

Step-by-step explanation:

Because....

if you use the slope formula y2-y1/y2-y1 .

It's going to be....

m=\frac{9-(-3)}{5-(-3)}

Therefor, the answer is m =  \frac{3}{2}

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8 0
3 years ago
In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t
Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

What is the probability that a randomly selected family owns a cat?

34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

5 0
2 years ago
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