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Vitek1552 [10]
3 years ago
12

It took 1.5 hours for a bus to go from one city to the next. The bus traveled at an average velocity of 52mph, west. How far apa

rt were the two cities?
A) 78 mi
B) 35 mi
C) 0.029 mi
D) 0.013 mi
Physics
2 answers:
Elina [12.6K]3 years ago
8 0

Answer: <u><em>78 miles apart     if i can get brainliest that would be great </em></u>

Speed is given by dividing distance by time.

That is; speed = distance/time

In this case; speed = 52 mph and the time is 1.5 hours

Distance= speed × time

Thus;  Distance = 52 × 1.5

                         = 78 miles

Thus the cities are 78 miles apart

arsen [322]3 years ago
8 0
THE ANSWER IS A AND I JNOW BECAUSE I TOOK THE TEST, so you welcome
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In a hydraulic lift, if the pressure exerted on the liquid by one piston is increased by 100 N/m2 , how much additional weight c
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Answer:

The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.

Explanation:

By means of the Pascal's Principle, the hydraulic lift can be modelled by the following two equations:

Hydraulic Lift - Before change

P = \frac{F}{A}

Hydraulic Lift - After change

P + \Delta P = \frac{F + \Delta F}{A}

Where:

P - Hydrostatic pressure, measured in pascals.

\Delta P - Change in hydrostatic pressure, measured in pascals.

A - Cross sectional area of the hydraulic lift, measured in square meters.

F - Hydrostatic force, measured in newtons.

\Delta F - Change in hydrostatic force, measured in newtons.

The additional weight is obtained after some algebraic handling and the replacing of all inputs:

\frac{F}{A} + \Delta P = \frac{F}{A} + \frac{\Delta F}{A}

\Delta P = \frac{\Delta F}{A}

\Delta F = A\cdot \Delta P

Given that \Delta P = 100\,Pa and A = 25\,m^{2}, the additional weight is:

\Delta F = (25\,m^{2})\cdot (100\,Pa)

\Delta F = 2500\,N

The additional mass needed for the additional weight is:

\Delta m = \frac{\Delta F}{g}

Where:

\Delta F - Additional weight, measured in newtons.

\Delta m - Additional mass, measured in kilograms.

g - Gravitational constant, measured in meters per square second.

If \Delta F = 2500\,N and g = 9.807\,\frac{m}{s^{2}}, then:

\Delta m = \frac{2500\,N}{9.807\,\frac{m}{s^{2}} }

\Delta m = 254.92\,kg

The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.

3 0
3 years ago
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