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alexandr402 [8]
3 years ago
9

Imagine that Kevin can instantly transport himself between Planet X and Planet Y. Which statement could be said about Kevin in t

his situation?
Kevin’s weight may change between Planet X and Planet Y.
Kevin’s volume may change between Planet X and Planet Y.
Kevin’s mass may change between Planet X and Planet Y.
Kevin’s matter may change between Planet X and Planet Y.
Physics
2 answers:
malfutka [58]3 years ago
5 0

Answer:

the answer is A

Explanation:

Elden [556K]3 years ago
3 0

The answer is Kevin's weight may change between Planet X and Planet Y.

<u>Explanation</u>:

  • The mass is the amount of matter contained in our body and it does not vary with other planets (remains constant). But the weight on the planet is the strength of gravity on the planet and result of mass which will vary with different planets. Your weight is a measure of the pull of gravity between the person and the planet.
  • Every object in the universe will attract each other object with the same mass. When the gravity is high, your weight will be high because your weight will be depending on the gravitational pull of planets.
  • For example, if an astronaut travels from Earth to Mars, his mass remains unchanged and he floats with the same size and mass but his weight will vary due to varying gravity. Thus your mass doesn't affect other planets it's only the weight that may change due to the varying gravitational pull or no gravity.
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The key differences between rotational kinematics and translational kinematics is: A. Rotational kinematics must specify an axis
inn [45]

In Translational motion, the body moves in a straight line whereas in Rotational motion, the body moves in a circular path.

<h3>Differences between rotational kinematics and translational kinematics</h3>

In Translational motion, the body moves in a straight line and the body same displacement in equal interval of time while on the other hand, in Rotational motion, the body moves in a circular path and the body travels same angular displacement in equal interval of time..

Learn more about motion here: brainly.com/question/453639

8 0
2 years ago
In a displacement versus time graph, what does the slope of a line at any point indicate?
Rom4ik [11]

In a displacement versus time graph, the slope of the line at any point on the graph indicates the <em>magnitude of velocity</em>.  

(It can't indicate velocity completely, because the graph shows nothing about the direction of the motion.)

4 0
3 years ago
Read 2 more answers
You are driving to the grocery store at 14 m/s. You are 115 m from an intersection when the traffic light turns red. Assume that
kogti [31]

Answer:

111.5 m

Explanation:

Given that You are driving to the grocery store at 14 m/s. You are 115 m from an intersection when the traffic light turns red. Assume that your reaction time is 0.50 s and that your car brakes with constant acceleration. 

Use first equation of motion

V = U - at

Since the car is going to rest, V = 0 and a = negative

0 = 14 - a × 0.5

0.5a = 14

a = 14 /0.5

a = 28 m/s^2

Let us use second equation of motion

S = Ut - 1/2at^2

S = 14 × 0.5 - 0.5 × 28 × 0.5^2

S = 7 - 3.5

S = 3.5 m

115 - 3.5 = 111.5

Therefore, you are 111.5 metres from the intersection (in m) when you begin to apply the brakes.

6 0
3 years ago
The radius of curvature of a spherical mirror is 20cm.What is its focal length?
hichkok12 [17]

Answer:

\boxed{\sf Focal \ length = 10 \ cm}

Given:

Radius of curvature (R) of a spherical mirror = 20

To Find:

Focal length (f)

Explanation:

Formula:

\boxed{ \bold{\sf Focal \ length \ (f) = \frac{Radius \ of \ curvature \ (R)}{2}}}

Substituting value of R in the equation:

\sf \implies f =  \frac{20}{2}

\sf \implies f = \frac{ \cancel{2} \times 10}{ \cancel{2}}

\sf \implies f = 10 \: cm

5 0
3 years ago
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a basketball player can leap upward .65m how long does the basketball player remain in the air use 9.81m/s²​
tigry1 [53]

At the player's maximum height, their velocity is 0. Recall that

{v_f}^2-{v_i}^2=2a\Delta y

which tells us the player's initial velocity v_i is

0^2-{v_i}^2=-2g(0.65\,\mathrm m)\implies v_i=3.6\dfrac{\rm m}{\rm s}

The player's height at time t is given by

y=v_it-\dfrac g2t^2

so we find their airtime to be

0.65\,\mathrm m=\left(3.6\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2\implies t=0.36\,\mathrm s

6 0
3 years ago
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