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alexandr402 [8]
3 years ago
9

Imagine that Kevin can instantly transport himself between Planet X and Planet Y. Which statement could be said about Kevin in t

his situation?
Kevin’s weight may change between Planet X and Planet Y.
Kevin’s volume may change between Planet X and Planet Y.
Kevin’s mass may change between Planet X and Planet Y.
Kevin’s matter may change between Planet X and Planet Y.
Physics
2 answers:
malfutka [58]3 years ago
5 0

Answer:

the answer is A

Explanation:

Elden [556K]3 years ago
3 0

The answer is Kevin's weight may change between Planet X and Planet Y.

<u>Explanation</u>:

  • The mass is the amount of matter contained in our body and it does not vary with other planets (remains constant). But the weight on the planet is the strength of gravity on the planet and result of mass which will vary with different planets. Your weight is a measure of the pull of gravity between the person and the planet.
  • Every object in the universe will attract each other object with the same mass. When the gravity is high, your weight will be high because your weight will be depending on the gravitational pull of planets.
  • For example, if an astronaut travels from Earth to Mars, his mass remains unchanged and he floats with the same size and mass but his weight will vary due to varying gravity. Thus your mass doesn't affect other planets it's only the weight that may change due to the varying gravitational pull or no gravity.
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In the first-order spectrum, maxima for two different wavelengths are separated on the screen by 3.40 mm . what is the differenc
Strike441 [17]

The solution would be like this for this specific problem:

 

Given:  

diffraction grating slits = 900 slits per centimeter

interference pattern that is observed on a screen from the grating = 2.38m

maxima for two different wavelengths = 3.40mm

 

slit separation .. d = 1/900cm = 1.11^-3cm = 1.111^-5 m <span>

Whenas n = 1, maxima (grating equation) sinθ = λ/d 
Grant distance of each maxima from centre = y .. 
<span>As sinθ ≈ y/D  y/D = λ/d λ = yd / D </span>

∆λ = (λ2 - λ1) = y2.d/D - y1.d/D 
∆λ = (d/D) [y2 -y1] 

<span>∆λ = 1.111^-5m x [3.40^-3m] / 2.38m .. .. ►∆λ = 1.587^-8 m</span></span>

6 0
4 years ago
Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is th
katrin [286]

Complete Question

Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is the nail compressed if it is 2.50 mm in diameter and 6.00-cm long.What Average force is excreted on the Nail

Answer:

F=2*10^{4}N

Explanation:

From the question we are told that:

Mass m=0.500kg

Initial Velocity V=15.0m/s

Distance x=2.80mm=>0.00280m

Diameter d=2.50mm=>0.00250m

Length l=6.00cm=>0.6m

Generally the equation for Force is mathematically given by

 F=\frac{mv^2}{2d}

 F=\frac{0.500*15^2}{2.80*10^{-3}}

 F=2*10^{4}N

6 0
3 years ago
A 2100 g block is pushed by an external force against a spring (with a 22 N/cm spring constant) until the spring is compressed b
Vilka [71]

Answer:

6.5e-4 m

Explanation:

We need to solve this question using law of conservation of energy

Energy at the bottom of the incline= energy at the point where the block will stop

Therefore, Energy at the bottom of the incline consists of the potential energy stored in spring and gravitational potential energy=\frac{1}{2} kx^{2} +PE1

Energy at the point where the block will stop consists of only gravitational potential energy=PE2

Hence from Energy at the bottom of the incline= energy at the point where the block will stop

⇒\frac{1}{2} kx^{2} +PE1=PE2

⇒PE2-PE1=\frac{1}{2} kx^{2}

Also PE2-PE2=mgh

where m is the mass of block

g is acceleration due to gravity=9.8 m/s

h is the difference in height between two positions

⇒mgh=\frac{1}{2} kx^{2}

Given m=2100kg

k=22N/cm=2200N/m

x=11cm=0.11 m

∴2100*9.8*h=\frac{1}{2}*2200*0.11^{2}

⇒20580*h=13.31

⇒h=\frac{13.31}{20580}

⇒h=0.0006467m=6.5e-4

7 0
4 years ago
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iren2701 [21]
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LiRa [457]

Answer:

False

Explanation:

5 0
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