Ultravoilent rays is an type of an electromegnetic wave with wavelength 10nm .Ultraviolet wave is used by doctors in order to keep the wounds away from bacteria.
<h3>What is ultravoilent wave ?</h3>
Ultravoilent rays is an type of an electromegnetic wave with wavelength 10nm. Ultravoilent wave is directly comes frim the sun. It is classified into the UV(A) , UV(B),UV(B).
Ultravoilet rays also effects the human eyes that s why sun glasses are used. The experiments here are compared and quantified to the effectiveness of the sunscreens with various strengths.
To learn more about the ultravoilent wave refr to the link;
brainly.com/question/19706211
Answer:
The force is 
Explanation:
From the question we are told that
The length of the box is 
The width of the box is 
The height is 
The pressure experience on one of the sides is mathematically represented as
Where A is the area of the box which is mathematically evaluated as

substituting values


This pressure is equivalent to the atmospheric pressure which has a constant value of 
This implies that

=> 
=> 
Answer:

Explanation:
As per energy conservation we know that the electrostatic potential energy of the charge system is equal to the initial kinetic energy of the alpha particle
So here we can write it as

now we know that


z = 79
here kinetic energy of the incident alpha particle is given as

now we have

now we have

For a standing wave on a string, the wavelength is equal to twice the length of the string:

In our problem, L=50.0 cm=0.50 m, therefore the wavelength of the wave is

And the speed of the wave is given by the product between the frequency and the wavelength of the wave: