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horsena [70]
3 years ago
9

What is the measurement 111.009 mm rounded off to four significant digits?

Physics
1 answer:
dedylja [7]3 years ago
4 0
111.0 because 111.009 rounds off to 111.01, thus rounding again off to 111.0
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What two things are needed to create an emission nebula? A) interstellar gas and dust B) hydrogen fusion and helium ionization C
wolverine [178]

Answer:

D) hot stars and interstellar gas, particularly hydrogen

Explanation:

Emission nebula is the nebula which is formed of the ionized gases which emit light of different wavelengths. The common source of ionization of the emission nebula is high-energy photons mostly which are emitted from hot star present nearby to it.

<u>The emission nebulae include H II regions. An H II region is the region of the interstellar atomic hydrogen which is ionized. It is the cloud of the partially ionized gas in which star formation takes place.</u>

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3 years ago
What is the kinetic energy of a 24-kg mass that is moving with a velocity of 2 m/s?
Anton [14]

Answer:

1/2mv^2

1/2*24*2^2

answer=48

3 0
3 years ago
Read 2 more answers
a car climbs 10.0 kilometers up a hill that inclines 8.0 degrees. what is the car's vertical displacement.
lakkis [162]
Ok so the answer will be 1.39km. 

First use SOH-CAH-TOA

Sine (SOH)=Opp/Hyp

Sin (8°) = vertical height/hypotenuse
Hypotenuse = 10 km
Vertical height =?
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I hope this helps. :3
4 0
3 years ago
How does the mass of an object affect its acceleration?
solong [7]

Answer:

as the mass of an object is increased, the acceleration of the object is decreased & vice-versa.

Explanation:

hope this helps!

3 0
2 years ago
A salt shaker sits 0.102 m from
Ivahew [28]

The maximum speed is 0.55 m/s

Explanation:

For an object in uniform circular motion, the force of friction between the object and the ground provides the centripetal force required to keep the body in motion. Therefore we can write:

\mu_s mg = m\frac{v^2}{r}

where the term on the left is the frictional force and the term on the right is the centripetal force, and where

\mu_s is the coefficient of static friction

m is the mass of the body

g is the gravitational acceleration

v is the speed of the body

r is the radius of the circular path

In this problem, we have:

\mu_s = 0.307

r = 0.102 m

g=9.8 m/s^2

Substituting and re-arranging, we find the maximum speed v at which the salt shaker can rotate:

v=\sqrt{\mu gr}=\sqrt{(0.307)(9.8)(0.102)}=0.55 m/s

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

6 0
3 years ago
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