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Alecsey [184]
3 years ago
12

When plugging in metric facts, always remember that 1 big unit = # small units. Fill in these facts: 1.________ s= ________μs 2.

____1____ g = 0.001________ kg 3._______ km = ________m 4.________mm = _______ m 5.________mL = ______ L 6._________g = ______ dg 7.________cm = _______ m 8.________ms = ________s
Physics
1 answer:
balandron [24]3 years ago
4 0

Answer:

1. 1 s = 1 x 10⁶ μs

2. 1 g = 0.001 kg

3. 1 km = 1000 m

4. 1 mm = 1 x 10⁻³ m

5. 1 mL = 1 x 10⁻³ L  

6. 1 g = 100 dg

7. 1 cm = 1 x 10⁻² m

8. 1 ms = 1 x 10⁻³ s

Explanation:

1.

1 x 10⁻⁶ s = 1 μs

(1 x 10⁻⁶ x 10⁶) s = 1 x 10⁶ μs

<u>1 s = 1 x 10⁶ μs</u>

2.

1000 g = 1 kg

1 g = 1/1000 kg

<u>1 g = 0.001 kg</u>

3.

<u>1 km = 1000 m</u>

<u></u>

4.

<u>1 mm = 1 x 10⁻³ m</u>

<u></u>

5.

<u>1 mL = 1 x 10⁻³ L</u>

<u></u>

6.

1 x 10⁻² g = 1 dg

(1 x 10⁻² x 10²) g = 1 x 10² dg

<u>1 g = 100 dg</u>

<u></u>

7.

<u>1 cm = 1 x 10⁻² m</u>

<u></u>

8.

<u>1 ms = 1 x 10⁻³ s</u>

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Do you think toxicity is a qualitative or quantitative property? explain
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3 years ago
An earthquake produces longitudinal P waves that travel outward at 8000 m/s and transverse S waves that move at 4500 m/s. A seis
vivado [14]

Answer:

1234285.7 m or 1234.3 km

Explanation:

Let the distance be d, the time taken by P waves be t_P and the time taken by the S waves be t_S.

\text{Velocity}\dfrac{\text{Distance}}{\text{Time}}

\text{Time}\dfrac{\text{Distance}}{\text{Velocity}}

For the P waves,

t_P=\dfrac{d}{8000}

d=8000t_P

For the S waves,

t_S=\dfrac{d}{4500}

d=4500t_S

Equating the d,

8000t_P=4500t_S

Divide both sides of the equation by 500 to reduce the terms.

16t_P=9t_S

Since S waves arrive 2 minutes (= 120 seconds) after P waves,

t_S-t_P=120

t_S=120+t_P

Substitute this in the equation of the distance.

16t_P=9(t_P+120)

16t_P=9t_P+1080

7t_P=1080

t_P=\dfrac{1080}{7}

Substitute this in the equation for d involving t_P.

d=8000t_P

d=8000\times\dfrac{1080}{7}

d=1234285.7 \text{ m }= 1234.3 \text{ km}

4 0
3 years ago
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