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Veseljchak [2.6K]

2 years ago

9

how does gravity affect objects of different mass close to earth, and how does that effect change as an object moves farther fro

m earth?

1 answer:

Luda [366]2 years ago

3 0

Answer:

It makes it lighter when its closer and heavier when its farther way.

Explanation:

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A moonshiner makes the error of filling a glass jar to the brim and capping it tightly. The moonshine expands more than the glas

ohaa [14]

Answer:

ΔP = (640 N/cm^2)

Explanation:

Given:-

- The volume increase, ΔV/V0 = 4 ✕ 10^-3

- The Bulk Modulus, B = 1.6*10^9 N/m^2

Find:-

Calculate the force exerted by the moonshine per square centimeter

Solution:-

- The bulk modulus B of a material is dependent on change in pressure or Force per unit area and change in volume by the following relationship.

B = ΔP / [(ΔV/V)]

- Now rearrange the above relation and solve for ΔP or force per unit area.

ΔP = B* [(ΔV/V)]

- Plug in the values:

ΔP = (1.6*10^9)*(4 ✕ 10^-3)

ΔP = 6400000 N/m^2

- For unit conversion from N/m^2 to N/cm^2 we have:

ΔP = (6400000 N/m^2) cm^2 / (100)^2 m^2

ΔP = (640 N/cm^2)

7 0

3 years ago

9. Know the three types of muscles, their shape, and where they are located.

KatRina [158]

Cardiac, smooth, and skeletal. cardiac muscle cells are located in the walls of the heart and appear striated and are under involuntary control. smooth muscle fibers are located in walls of hollow visceral organs except the heart they also appear striated. skeleton muscle is found between bones and uses tendons to connect to the epimysium to the periosteum, or the outer covering of bone. skeletal muscle is shaped and adapted in many ways.

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8 0

3 years ago

List atleast 10 applications of chemical effect of electric current

Komok [63]

Answer:

formation of gas bubbles at electrodes

deposition of metals at electrodes

changes in solution colour

electroplating

electrolysis

4 0

3 years ago

Pls help! True or False?

jasenka [17]

Answer:

True

Explanation:

i hope it helps

please follow me

7 0

2 years ago

Read 2 more answers

You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi

Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0

3 years ago