<em>Answer:</em>
<em>B.) A hot liquid or air that expands, becomes less dense, and rises or becomes more dense and sinks.</em>
<em>Explanation:</em>
<em>Convention is the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat.</em>
Answer:
Explanation:
<u>1. Word equation:</u>
- <em>mercury(II) oxide → mercury + oxygen </em>
<u>2. Balanced molecular equation:</u>
<u>3. Mole ratio</u>
Write the ratio of the coefficients of the substances that are object of the problem:

<u>4. Calculate the number of moles of O₂(g)</u>
Use the equation for ideal gases:

<u>5. Calculate the number of moles of HgO</u>

<u>6. Convert to mass</u>
- mass = # moles × molar mass
- molar mass of HgO: 216.591g/mol
- mass = 0.315mol × 216.591g/mol = 68.3g
The gravitational force is related to the distance between two objects because it is inversely proportional to the square of the distance.
<h3>What is the gravitational force?</h3>
The gravitational force refers to the attraction between two different objects due to their masses.
This force (gravitational force) is fundamental for maintaining the distance of objects in the Universe.
In conclusion, the gravitational force is related to the distance between two objects because it is inversely proportional to the square of the distance.
Learn more about gravitational force here:
brainly.com/question/72250
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<u>Answer:</u> The value of
for the net reaction is 
<u>Explanation:</u>
The given chemical equations follows:
<u>Equation 1:</u> 
<u>Equation 2:</u> 
The net equation follows:
As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.
The value of equilibrium constant for net reaction is:

We are given:


Putting values in above equation, we get:

Hence, the value of
for the net reaction is 