Answer:
Final pressure of the gas remaining in the first container is 3.5 atm
Explanation:
Since it is given that temperature is constant , we can apply -
PV=constant , where
P = Pressure of the gas
V = Volume of the container in which the gas is contained
Initially,
For container 1 -
= 4 atm
= 6 L
Finally,
For container 2 -
= 3 atm
= 1 L
For container 1 -
= ?
= 6 L
∴ 
= 
+ 

∴ 4×6 = (
×6) +(3×1)
∴
= 3.5 atm
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