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Fudgin [204]
3 years ago
6

About which of the following can you ask scientific questions

Chemistry
1 answer:
Stels [109]3 years ago
8 0
<h2>Answer:</h2>

Scientific questions are question which are solved involving experiments, observations, or surveys.

Like, Is cancer caused by uncontrolled cell division.

<h3>Explanation:</h3>

Scientific questions are always testable questions. They can be solved by using scientific techniques like PCR, titration etc.

Here the given question in the example can be tested, by making the observations of the cell division of the cancer patients. Then by inducing uncontrolled cell division into normal cells to look for the effect of cell division on cancer.

The questions like, "is sadness can be controlled by talking?" is not a scientific question.

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C: Ms. Bakare has two bottles of sulfuric acid, X and Y. There is one litre of acid in each bottle.
umka2103 [35]

Acid of x bottle is highly reactive because solute is more and acid of y bottle is less reactive because solvent is more.

8 0
2 years ago
Photochemical smog results from the interaction of pollutants in the presence of
atroni [7]

Water vapor in the air

5 0
3 years ago
Which of the following is a half-reaction? A. Zn+CuSO4−&gt; B. 2Cl−−&gt;Cl2+2e− C. H2+1/2O2−&gt;H2O D. −&gt;Cu+ZnSO4
malfutka [58]

Answer:

2Cl——>Cl2+2e-

Explanation:

It shows an electron loss or gain

8 0
3 years ago
Assume that silver and gold form ideal, random mixtures. Calculate the mass of pure Ag needed to cause an entropy increase of 20
KengaRu [80]

Answer:

m_{Ag}=2,265.9g

Explanation:

Hello!

In this case, since the definition of entropy in a random mixture is:

\Delta S=-n_TR\Sigma[x_i*ln(x_i)]

For this silver-gold mixture we write:

\Delta S=-(n_{Au}+n_{Ag})R\Sigma[\frac{n_{Au}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Au}}{n_{Au}+n_{Ag}} )+\frac{n_{Ag}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Ag}}{n_{Au}+n_{Ag}} )]

By knowing the moles of gold:

n_{Au}=100g*\frac{1mol}{197g} =0.508mol

It is possible to write the aforementioned formula in terms of the variable x representing the moles of silver:

20\frac{J}{mol}=-(0.508+x)8.314\frac{J}{mol*K} \Sigma[\frac{0.508}{0.508+x} *ln(\frac{0.508}{0.508+x} )+\frac{x}{0.508+x} *ln(\frac{x}{0.508+x} )]

Which can be solved via Newton-Raphson or a solver software, in this case, I will provide you the answer:

x=n_{Ag}=21.0molAg

So the mass is:

m_{Ag}=21.0mol*\frac{107.9g}{1mol}\\ \\m_{Ag}=2,265.9g

Best regards!

3 0
3 years ago
Chemical formula for sodium and sulfur
Nookie1986 [14]
The chemical formula for sodium and sulfur is Na2S I believe...
8 0
2 years ago
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