All categories

2 years ago

How did Ernest Rutherford’s experiment relate to J.J. Thomson’s work?

1 answer:

8 0

Thomson realized that the accepted model of an atom did not account for negatively or positively charged particles. Therefore, he proposed a model of the atom which he likened to plum pudding. ... Rutherford with the assistance of Ernest Marsden and Hans Geiger performed a series of experiments using alpha particles.

You might be interested in

Convert 22.5 grams H2O to moles

kenny6666 [7]

Answer:

18.01528

Explanation:

The answer is 18.01528.

4 0

3 years ago

Read 2 more answers

A chemical reaction produces 11.8 moles of tin atoms how many grams of tin are made

valina [46]

Convert mols to grams by multiplying grams of tin by the number of mols.

There are 119 grams per mol

119 x 11.8 = 1404 grams

7 0

2 years ago

4 NH3 + 6 NO → 5 N2 + 6 H2O How many moles of NH3 are necessary to produce 0.824 mol N2?

GrogVix [38]

4 mol NH₃ → 5 mol N₂
x mol NH₃ → 0.824 mol N₂

x=0.824*4/5=0.6592 mol

6 0

3 years ago

Will mark the brainiest later for correct answers! Please show work.

Elodia [21]

Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}$

a. moles in 14.08 g of $C_{12}H_{22}O_{11}$ = $\frac{14.08g}{342.3g/mol}=0.04113moles$

molecules in 14.08 g of $C_{12}H_{22}O_{11}$ = $0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}$

b. moles in 17.75 g of NaCl = $\frac{17.75g}{58.5g/mol}=0.3034moles$

molecules in 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

formula units 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

c. moles in 20.06 g of $CuSO_4.5H_2O$ = $\frac{20.06g}{249.68g/mol}=0.08034moles$

formula units in 20.06 g of $CuSO_4.5H_2O$ = $0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}$

7 0

3 years ago

I BEG YOU I NEED IT TILL 12 PLEASE ILL GIVE THE BRAINLEST AND HEARTS AND POINTS HELP PLEASEEEE !!!!!!!!!!!!!!!!!!!!!!!!!

Lubov Fominskaja [6]

UHHHHHHHH IDRK TRY THE LINK ABOVE

3 0

2 years ago

Read 2 more answers