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Mars2501 [29]
2 years ago
10

A solution is 5.00% by volume of ethanol dissolved in water. How many mL of ethanol are in 500 mL of the solution?

Chemistry
1 answer:
fiasKO [112]2 years ago
8 0

Answer:

v_{solute}=25mL

Explanation:

Hello there!

In this case, according to the by-volume concentration of this solution, it is possible for us to use its mathematical definition as shown below:

\%v=\frac{v_{solute}}{v_{solution}}*100\%

Thus, given the percent and the volume of the solution, we can solve for the volume of ethanol (solute) as shown below:

v_{solute}=\frac{\%v*v_{solution}}{100\% }\\\\v_{solute}=\frac{5.00\%*500mL}{100\%}\\\\ v_{solute}=25mL

Best regards!

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1. NaN₃(s) → Na(s) + 1.5 N₂(g)

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<em>1. Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN₃) into solid sodium and gaseous dinitrogen.</em>

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<em>2. Suppose 43.0L of dinitrogen gas are produced by this reaction, at a temperature of 13.0°C and pressure of exactly 1atm. Calculate the mass of sodium azide that must have reacted. Round your answer to 3 significant digits.</em>

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1.83molN_{2}.\frac{1molNaN_{3}}{1.5molN_{2}} =1.22molNaN_{3}

The molar mass of NaN₃ is 65.01 g/mol. The mass of NaN₃ is:

1.22mol.\frac{65.01g}{mol} =79.3g

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