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Sliva [168]
3 years ago
12

Check all items common to bases:

Chemistry
2 answers:
amm18123 years ago
4 0

Answer:

The correct answer is "e= -OH"

Explanation:

Hello! Let's solve this!

A substance that is a base has -OH

According to Arrhenius, a base is a substance that gives -OH to the medium.

An acid, according to Arrehnius, is a substance that can accept protons (H +)

The correct answer is "e= -OH"

Leona [35]3 years ago
3 0
The common to bases is
<span>e-OH-
according to the characteristics of Arrhenius bases.

An Arrhenius base is a substance that produces OH- or hydroxide ions when dissolved in water. An Arrhenius acid, on the other hand, produces H+ ions when dissolved in water.</span>
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4,3,1,2 thise is my answer.

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10mL volume of 75mM EtOH is necessary for an experiment. What volumes of 1M EtOH and water should be mixed to obtain the working
kenny6666 [7]

Answer: Volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration.

Explanation:

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = molarity of stock solution = 1M

V_1 = volume of stock solution = ?

C_2 = molarity of diluted solution = 0.075 M    (1mM=0.001M)

V_2 = volume of diluted solution = 10 ml

Putting in the values we get:

1M\times V_1=0.075M\times 10ml

V_1=0.75ml

Thus 0.75 ml of 1M EtOH is taken and (10-0.75)ml = 9.25 ml of water is added to make the volume 10ml.

Therefore, volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration

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3 years ago
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Using the balanced equation N2+O2=2NO, how many grams of NO can be produced when 25.0 grams of N react?
Oxana [17]

Answer:

53.55gNO

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to calculate the produced grams of nitrogen monoxide by starting with 25.0 g of nitrogen via their 1:2 mole ratio and the molar masses of 30.1 g/mol and 28.02 g/mol, respectively and by some stoichiometry:

=25.0gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNO}{1molN_2}*\frac{30.01 gNO}{1molNO}\\\\=53.55gNO

Best regards!

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