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Lynna [10]
2 years ago
7

Please help with that problem Important İ have quiz tomorrow

Chemistry
1 answer:
iogann1982 [59]2 years ago
6 0

Answer:

Final pressure of the gas remaining in the first container is 3.5 atm

Explanation:

Since it is given that temperature is constant , we can apply -

PV=constant , where

P = Pressure of the gas

V = Volume of the container in which the gas is contained

Initially,

For container 1 -

P_{i} = 4 atm

V_{1} = 6 L

Finally,

For container 2 -

P_{f,2} = 3 atm

V_{2} = 1 L

For container 1 -

P_{f,1} = ?

V_{1} = 6 L

∴ P_{i}V_{1} = P_{f,1}V_{1} + P_{f,2}V_{2}

∴ 4×6 =  (P_{f,1}×6) +(3×1)

∴ P_{f,1} = 3.5 atm

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Answer:

If a gas has experienced a small increase in volume but has maintained the same pressure and number of moles, the temperature of the gas will DROP.

Explanation:

According to Boyle’s law of ideal gases, volume and temperature of a gas is inversely related, as long as the pressure is kept constant;

P₁V₁/T₁ = P₂V₂/T₂

Therefore, if the volume of the gas increases, the temperature will definitely decrease due to the inverse relationship. The gas will get cooler.  

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3 years ago
When a radioactive isotope releases an alpha particle, the atomic number of the atom is (2 points)
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3 years ago
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A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?
Colt1911 [192]

Answer:

571.81 mL

Explanation:

Assuming constant pressure, we can solve this problem by using <em>Charles' law</em>, which states that at constant pressure:

  • V₁T₂=V₂T₁

Where in this case:

  • V₁ = 852 mL
  • T₂ = 200 K
  • V₂ = ?
  • T₁ = 298 K

We <u>input the data</u>:

  • 852 mL * 200 K = V₂ * 298 K

And <u>solve for V₂</u>:

  • V₂ = 571.81 mL

The new volume would be 571.81 mL.

4 0
3 years ago
A weather balloon has a volume of 105L at 0.97 atm when the temperature is 318K. What is the volume
chubhunter [2.5K]

Answer:

89 L

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 0.97 atm
  • Initial volume (V₁): 105 L
  • Initial temperature (T₁): 318 K
  • Final pressure (P₂): 1.05 atm
  • Final volume (V₂): ?
  • Final temperature (T₂): 293 K

Step 2: Calculate the final volume of the weather balloon

If we assume that the gas inside the balloon behaves as an ideal gas, we can calculate the final volume of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 0.97 atm × 105 L × 293 K / 318 K × 1.05 atm = 89 L

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2 years ago
The specific heat values of most _____ tend to be quite low
GrogVix [38]
This answer would be heat capacity
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3 years ago
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