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Lynna [10]
3 years ago
7

Please help with that problem Important İ have quiz tomorrow

Chemistry
1 answer:
iogann1982 [59]3 years ago
6 0

Answer:

Final pressure of the gas remaining in the first container is 3.5 atm

Explanation:

Since it is given that temperature is constant , we can apply -

PV=constant , where

P = Pressure of the gas

V = Volume of the container in which the gas is contained

Initially,

For container 1 -

P_{i} = 4 atm

V_{1} = 6 L

Finally,

For container 2 -

P_{f,2} = 3 atm

V_{2} = 1 L

For container 1 -

P_{f,1} = ?

V_{1} = 6 L

∴ P_{i}V_{1} = P_{f,1}V_{1} + P_{f,2}V_{2}

∴ 4×6 =  (P_{f,1}×6) +(3×1)

∴ P_{f,1} = 3.5 atm

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Here's what I get.

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