Answer:
If a gas has experienced a small increase in volume but has maintained the same pressure and number of moles, the temperature of the gas will DROP.
Explanation:
According to Boyle’s law of ideal gases, volume and temperature of a gas is inversely related, as long as the pressure is kept constant;
P₁V₁/T₁ = P₂V₂/T₂
Therefore, if the volume of the gas increases, the temperature will definitely decrease due to the inverse relationship. The gas will get cooler.
Learn More:
For more on Boyle's Law check out;
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When alpha decay takes place, two protons and two neutrons are forcefully ejected from the nucleus in a way that looks very similar to a Helium nucleus. This type of decay causes the atomic mass of the parent particle to drop by four (four particles lost), but the atomic number drops by only two (two protons lost). Therefore, your answer is C.
Answer:
571.81 mL
Explanation:
Assuming constant pressure, we can solve this problem by using <em>Charles' law</em>, which states that at constant pressure:
Where in this case:
We <u>input the data</u>:
- 852 mL * 200 K = V₂ * 298 K
And <u>solve for V₂</u>:
The new volume would be 571.81 mL.
Answer:
89 L
Explanation:
Step 1: Given data
- Initial pressure (P₁): 0.97 atm
- Initial volume (V₁): 105 L
- Initial temperature (T₁): 318 K
- Final pressure (P₂): 1.05 atm
- Final temperature (T₂): 293 K
Step 2: Calculate the final volume of the weather balloon
If we assume that the gas inside the balloon behaves as an ideal gas, we can calculate the final volume of the gas using the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
V₂ = P₁ × V₁ × T₂ / T₁ × P₂
V₂ = 0.97 atm × 105 L × 293 K / 318 K × 1.05 atm = 89 L
This answer would be heat capacity