1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hoa [83]
3 years ago
11

An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective

ly. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates. The appropriate chemical equation is:
PCl3(g) + Cl2(g) ---> PCl5(g)

Calculate the new partial pressures after equilibrium is reestablished. [in torr]

PPCl3

PPCl2

PPCl5
Chemistry
1 answer:
djverab [1.8K]3 years ago
5 0

Answer:

The new partial pressures after equilibrium is reestablished for PCl_3:

P_1'=6.798 Torr

The new partial pressures after equilibrium is reestablished Cl_2:

P_2'=26.398 Torr

The new partial pressures after equilibrium is reestablished for PCl_5:

P_3'=223.402 Torr

Explanation:

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At equilibrium before adding chlorine gas:

Partial pressure of the PCl_3=P_1=13.2 Torr

Partial pressure of the Cl_2=P_2=13.2 Torr

Partial pressure of the PCl_5=P_3=217.0 Torr

The expression of an equilibrium constant is given by :

K_p=\frac{P_1}{P_1\times P_2}

=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245

At equilibrium after adding chlorine gas:

Partial pressure of the PCl_3=P_1'=13.2 Torr

Partial pressure of the Cl_2=P_2'=?

Partial pressure of the PCl_5=P_3'=217.0 Torr

Total pressure of the system = P = 263.0 Torr

P=P_1'+P_2'+P_3'

263.0Torr=13.2 Torr+P_2'+217.0 Torr

P_2'=32.8 Torr

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At initail

(13.2) Torr     (32.8) Torr                        (13.2) Torr

At equilbriumm

(13.2-x) Torr     (32.8-x) Torr                        (217.0+x) Torr

K_p=\frac{P_3'}{P_1'\times P_2'}

1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished for PCl_3:

P_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr

The new partial pressures after equilibrium is reestablished Cl_2:

P_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr

The new partial pressures after equilibrium is reestablished for PCl_5:

P_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr

You might be interested in
How might a fact be disproved? Are there some facts that will never be disproved
Paha777 [63]
A fact can be disapproved with further evidence different details. So basically evidence can change a fact!! Hope this helps
7 0
3 years ago
A sample of lead with a mass of 54.3 g is heated to a temperature of 384.4 K and placed in a container of water at 291.2 K. The
DerKrebs [107]

The mass of the water in the container given the data from the question is 22.5 g

<h3>Data obtained from the question</h3>
  • Mass of cold lead (M) = 54.3 g
  • Temperature of lead (T) = 384.4 K
  • Temperature of water (Tᵥᵥ) = 291.2 K
  • Equilibrium temperature (Tₑ) = 297.6 K
  • Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gK
  • Specific heat capacity of lead (C) = 0.128 J/gK
  • Mass of water (Mᵥᵥ) = ?

<h3>How to determine the mass of water </h3>

Heat loss = Heat gain

MC(T – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

54.3 × 0.128 (384.4 – 297.6) = Mᵥᵥ × 4.184(297.6 – 291.2)

6.9504 × 86.8 = Mᵥᵥ × 4.184 × 6.4

Divide both side by 4.184 × 6.4

Mᵥᵥ = (6.9504 × 86.8) / (4.184 × 6.4)

Mᵥᵥ = 22.5 g

Learn more about heat transfer:

brainly.com/question/6363778

#SPJ1

8 0
2 years ago
Which of the following particle diagrams represents a mixture?
Sati [7]

Answer:

I know Z

Explanation:

because here is mixing two substance so there is mixture

4 0
3 years ago
How many grams of propane are in 20 pounds of propane? Use the conversion 1 lb = 454 g. (Express your answers for the next three
Dima020 [189]

Answer:

a. =9.1x10^3gC_3H_8

b. 2.1x10^2molC_3H_8

c. Q=-4.6x10^5kJ

Explanation:

Hello,

a. By applying the given information, one obtains:

20lbC_3H_8*\frac{454gC_3H_8}{1lbC_3H_8} =9.1x10^3gC_3H_8

b. By knowing that the propane has a molecular mass of 44g/mol, one obtains:

20lbC_3H_8*\frac{454gC_3H_8}{1lbC_3H_8}*\frac{1molC_3H_8}{44gC_3H_8} =2.1x10^2molC_3H_8

c. Here, the propane's combustion chemical reaction is stated:

C_3H_8+5O_2-->3CO_2+4H_2O

This enthalpy of reaction is computed via:

ΔrH=(3*-393.5kJ/mol)+(4*241kJ/mol)-(-104.7kJ/mol)=-2043kJ/mol

Finally, since it is done for 20 lb of propane (2.1x10^2molC_3H_8), the obtainable energy is:

Q=-2043kJ/mol*2.1x10^2molC_3H_8\\Q=-4.6x10^5kJ

Best regards.

4 0
3 years ago
Which of the following correctly defines transcription?
icang [17]
I would say is b. The answer
8 0
3 years ago
Read 2 more answers
Other questions:
  • It is possible for the transition metal zinc to form more than one possible ion
    6·1 answer
  • If the solid copper starts off at the normal melting temperature of copper and the liquid copper is put into the mold at the cry
    5·1 answer
  • Whats the atomic mass of an atom
    15·2 answers
  • Dehydration is a reversible process. Which of the two set-ups, distillation or
    8·1 answer
  • From goal line to goal line, a football field is 300 ft long. If a player catches the ball while standing on one goal line, runs
    5·1 answer
  • How many sulfur atoms are there in 4.45 mol of sulfur?
    8·1 answer
  • Balance Cl2+NaBr=NaCl+Br2​
    11·1 answer
  • Ag + HCl --&gt; ?<br> a) No reaction<br> b) AgCl + H2<br> c) AgCl + H2O<br> PLEASE HELP
    11·2 answers
  • What is the difference in chemical energy between organic and inorganic materials?
    9·1 answer
  • As atoms get smaller,valance electrons are getting closer or farther away?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!