The solution would be like this for this specific problem:
4 NaOCl + S2O3{2-} + 2
OH{-} → 2 SO4{2-} + H2O + 4 NaCl
<span>(0.00456 L) x (0.100 mol/L
S2O3{2-}) x (4 mol NaOCl / 1 mol S2O3{2-}) x (100.0 mL / 25 mL) x </span><span>
<span>(74.4422 g NaClO/mol) = 0.54313 g </span></span>
<span>(5.00 mL) x (1.08 g/mL) =
5.40 g solution </span>
(0.54313 g) / (5.40 g) =
0.101 = 10.1%
So, the average percent by mass of NaClO in the
commercial bleach is 10.1%.
Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the rate constant at 55 °C by using the temperature-variable version of the Arrhenius equation:
Thus, we plug in the temperatures, activation energy and universal constant of gases in consistent units to obtain:
Regards!
Answer:
D. Na₃X
Explanation:
We have the neutral compound Ba₃(X)₂. <em>The total charge (zero) is equal to the sum of the charges of the ions times the number of ions in the molecule</em>.
3 × qBa + 2 × qX = 0
3 × (+2) + 2 × qX = 0
2 × qX = -6
qX = -3
If we have the cation Na⁺ and X³⁻, a neutral molecule would require 3 Na⁺ and 1 X³⁻. The resulting compound is Na₃X.
