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notsponge [240]
3 years ago
10

Determine the volume, in liters, of 3.2 mol of CO2 gas at STP.

Chemistry
1 answer:
Allushta [10]3 years ago
6 0

Answer:

71.7 L

Explanation:

Using the ideal gas equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/Kmol)

T = temperature (K)

According to the information provided in this question;

P = 1 atm (STP)

V = ?

n = 3.2mol

T = 273K (STP)

Using PV = nRT

V = nRT/P

V = 3.2 × 0.0821 × 273/1

V = 71.7 L

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Find the volume of an object that has a mass of 20g and density of 184 glcm
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8 0
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2 NaCL + CaO = CaCL2 + Na2O
Naily [24]

222 grams of calcium chloride is produced.

<h3><u>Explanation</u>:</h3>

The mole concept and the chemical equation are very much closely related with each other. In the chemical reaction, the compounds or elements in both sides are balanced according to the number of atoms of each side of the reaction. So from there we can easily find the amount of reactant reacts to produce desired product.

Here we can see that 2 moles of sodium chloride produces 1 mole of calcium chloride.

So, 4 moles of sodium chloride will produce 2 moles of calcium chloride.

Now, atomic weight of calcium =40.

Atomic weight of chlorine =35.5.

So,the molecular weight of calcium chloride = 40+ 35.5\times2

=111.

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So 2 moles of calcium chloride weighs 111\times2 grams = 222 grams.

7 0
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Determine the grams of Iron(III) chloride produced if 22.5 g Iron reacts with Chlorine gas. First, balance the chemical equation
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3 years ago
You perform a distillation to separate a mixture of propylbenzene and cyclohexane, and you obtain 2.9949 grams of cyclohexane (d
Romashka-Z-Leto [24]

Answer:

66.67%

Explanation:

From the given information:

mass of cyclohexane = 2.9949 grams

density of cyclohexane = 0.779 g/mL

Recall that:

Density = mass/volume

∴

Volume = mass/density

So, the volume of cyclohexane = 2.9949 g/ 0.779 g/mL

= 3.8445 mL

Also,

mass of propylbenzene = 1.6575 grams

density of propylbenzene = 0.862 g/mL

Volume of propylbenzene =  1.6575 g/ 0.862 g/mL

= 1.9229 mL

The volume % composition of cyclohexane from the mixture is:

= (\dfrac{v_{cyclohexane}}{v_{cyclohexane}+v_{propylbenzene}})\times 100

= (\dfrac{3.8445}{3.8445+1.9229})\times 100

= (\dfrac{3.8445}{5.7674})\times 100

= 66.67%

6 0
3 years ago
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